<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Notes on AP Stat Home</title><link>https://ap-stat.zhtek.org/notes/</link><description>Recent content in Notes on AP Stat Home</description><generator>Hugo -- gohugo.io</generator><language>en-us</language><lastBuildDate>Tue, 07 Apr 2026 20:58:33 +0000</lastBuildDate><atom:link href="https://ap-stat.zhtek.org/notes/index.xml" rel="self" type="application/rss+xml"/><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-note-dec-19-2025/</link><pubDate>Tue, 07 Apr 2026 20:58:33 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-note-dec-19-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-note-dec-19-2025.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
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&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-note-dec-19-2025.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
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&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-note-dec-23-2025/</link><pubDate>Tue, 07 Apr 2026 20:58:31 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-note-dec-23-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-note-dec-23-2025.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-note-dec-23-2025.pdf#view=FitH"
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&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-note-dec-23-2025.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
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&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-prob-2-2/</link><pubDate>Tue, 07 Apr 2026 20:58:28 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-prob-2-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-prob-2-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
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&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-prob-2-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
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&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-note-dec-24-2025/</link><pubDate>Tue, 07 Apr 2026 20:58:26 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-note-dec-24-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-note-dec-24-2025.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-note-dec-24-2025.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
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&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-note-dec-24-2025.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-note-dec-26-2025/</link><pubDate>Tue, 07 Apr 2026 20:58:23 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-note-dec-26-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-note-dec-26-2025.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
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&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-note-dec-26-2025.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
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&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-homework-4/</link><pubDate>Tue, 07 Apr 2026 20:58:21 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-homework-4/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-homework-4.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-homework-4.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-homework-4.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-homework-2/</link><pubDate>Tue, 07 Apr 2026 20:58:18 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-homework-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-homework-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-homework-2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-homework-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-homework-1/</link><pubDate>Tue, 07 Apr 2026 20:58:16 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-homework-1/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-homework-1.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-homework-1.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
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&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-homework-1.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-note-jan-6-2026/</link><pubDate>Tue, 07 Apr 2026 20:58:13 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-note-jan-6-2026/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-note-jan-6-2026.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-note-jan-6-2026.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-note-jan-6-2026.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-prompt-guide/</link><pubDate>Tue, 07 Apr 2026 20:58:10 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-prompt-guide/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-prompt-guide.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-prompt-guide.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-prompt-guide.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-note-jan-7-2026/</link><pubDate>Tue, 07 Apr 2026 20:58:08 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-note-jan-7-2026/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-note-jan-7-2026.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-note-jan-7-2026.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-note-jan-7-2026.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-note-jan-6-2026-3-copy/</link><pubDate>Tue, 07 Apr 2026 20:58:05 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-note-jan-6-2026-3-copy/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-note-jan-6-2026-3-copy.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-note-jan-6-2026-3-copy.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-note-jan-6-2026-3-copy.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap3-review-bank-2-2/</link><pubDate>Tue, 07 Apr 2026 20:58:00 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap3-review-bank-2-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap3-review-bank-2-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP3/ap3-review-bank-2-2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP3/ap3-review-bank-2-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/secrets-review-bank-2-3/</link><pubDate>Tue, 07 Apr 2026 20:57:57 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/secrets-review-bank-2-3/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/secrets-review-bank-2-3.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> secrets | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/secrets/secrets-review-bank-2-3.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/secrets/secrets-review-bank-2-3.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-ap2/</link><pubDate>Tue, 07 Apr 2026 20:57:55 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-ap2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-ap2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-ap2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-ap2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-prob-3/</link><pubDate>Tue, 07 Apr 2026 20:57:51 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-prob-3/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-prob-3.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-prob-3.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
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&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-prob-3.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-prob/</link><pubDate>Tue, 07 Apr 2026 20:57:49 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-prob/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-prob.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-prob.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-prob.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-prob-2/</link><pubDate>Tue, 07 Apr 2026 20:57:46 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-prob-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-prob-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-prob-2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-prob-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-note-dec-25-2025/</link><pubDate>Tue, 07 Apr 2026 20:57:44 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-note-dec-25-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-note-dec-25-2025.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-note-dec-25-2025.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-note-dec-25-2025.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-binomial/</link><pubDate>Tue, 07 Apr 2026 20:57:40 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-binomial/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-binomial.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-binomial.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-binomial.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-homework-1-3/</link><pubDate>Tue, 07 Apr 2026 20:57:37 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-homework-1-3/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-homework-1-3.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-homework-1-3.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-homework-1-3.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-note-jan-4-2026/</link><pubDate>Tue, 07 Apr 2026 20:57:34 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-note-jan-4-2026/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-note-jan-4-2026.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-4-2026.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-4-2026.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-homework-4-2/</link><pubDate>Tue, 07 Apr 2026 20:57:30 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-homework-4-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-homework-4-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-homework-4-2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-homework-4-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-note-jan-6-2026-2/</link><pubDate>Tue, 07 Apr 2026 20:57:28 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-note-jan-6-2026-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-note-jan-6-2026-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-6-2026-2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-6-2026-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-note-jan-8-2026/</link><pubDate>Tue, 07 Apr 2026 20:57:25 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-note-jan-8-2026/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-note-jan-8-2026.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-8-2026.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-8-2026.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-note-jan-6-2026-3/</link><pubDate>Tue, 07 Apr 2026 20:57:23 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-note-jan-6-2026-3/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-note-jan-6-2026-3.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-6-2026-3.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-6-2026-3.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-note-jan-6-2026-3-copy/</link><pubDate>Tue, 07 Apr 2026 20:57:19 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-note-jan-6-2026-3-copy/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-note-jan-6-2026-3-copy.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-6-2026-3-copy.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-note-jan-6-2026-3-copy.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap2-review-bank/</link><pubDate>Tue, 07 Apr 2026 20:57:14 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2-review-bank/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2-review-bank.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP2/ap2-review-bank.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP2/ap2-review-bank.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap1-prob-2/</link><pubDate>Tue, 07 Apr 2026 20:57:11 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap1-prob-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap1-prob-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP1/ap1-prob-2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP1/ap1-prob-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap1-temp/</link><pubDate>Tue, 07 Apr 2026 20:57:08 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap1-temp/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap1-temp.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP1/ap1-temp.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP1/ap1-temp.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap1-temp-2/</link><pubDate>Tue, 07 Apr 2026 20:57:06 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap1-temp-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap1-temp-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP1/ap1-temp-2.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP1/ap1-temp-2.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap1-note-dec-22-2025/</link><pubDate>Tue, 07 Apr 2026 20:57:03 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap1-note-dec-22-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap1-note-dec-22-2025.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP1/ap1-note-dec-22-2025.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
&lt;/iframe>
&lt;/div>
&lt;p style="text-align: center; margin-top: 10px;">
&lt;a href="https://assets.zhtek.org/pdfs/AP1/ap1-note-dec-22-2025.pdf" target="_blank" class="btn btn-primary"
style="background: #007bff; color: white; padding: 8px 16px; text-decoration: none; border-radius: 4px;">Download PDF&lt;/a>
&lt;/p>
&lt;div style="display:none" class="ocr-index">
&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap1-binomial/</link><pubDate>Tue, 07 Apr 2026 20:57:00 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap1-binomial/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap1-binomial.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
&lt;div style="position: relative; padding-bottom: 141.4%; height: 0; overflow: hidden; max-width: 100%; background: #f8f9fa; border: 1px solid #dee2e6; border-radius: 8px;">
&lt;iframe src="https://assets.zhtek.org/pdfs/AP1/ap1-binomial.pdf#view=FitH"
style="position: absolute; top: 0; left: 0; width: 100%; height: 100%; border: 0;"
allowfullscreen>
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&lt;/div></description></item><item><title>Note Update: Untitled Note</title><link>https://ap-stat.zhtek.org/notes/ap1-note-jan-4-2026-2/</link><pubDate>Tue, 07 Apr 2026 20:56:57 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap1-note-jan-4-2026-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap1-note-jan-4-2026-2.webp" alt="Featured image of post Note Update: Untitled Note" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2026-04-07&lt;/p>
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&lt;/div></description></item><item><title>Note Update: Probability Rules, Random Variables, and Sampling Distributions Review</title><link>https://ap-stat.zhtek.org/notes/prob-2/</link><pubDate>Wed, 24 Dec 2025 04:53:44 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/prob-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/prob-2.webp" alt="Featured image of post Note Update: Probability Rules, Random Variables, and Sampling Distributions Review" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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1 Probability: General Rules, Independence, and Conditional Probability 1. A high school science teacher has 78 students. Of those students, 35 are in the band and 32 are on a sports team. There are 16 students who are not in the band or on a sports team. One student from the 78 students will be selected at random. Let event B represent the event of selecting a student in the band, and let event S represent the event of selecting a student on a sports team. Are B and S mutually exclusive events? A. No, because P(B∩S) = 5/78. B. No, because P(B∩S) = 48/78. C. No, because P(B∩S) = 62/78 D. Yes, because P(B∩S) = 5/78 E. Yes, because P(B∩S) = 62/78 P(A)= 1-P(A^c) P(A∪B)= P(A)+P(B) - P(A∩B) P(B)= 35/78 P(S)= 32/78 [P(B∪S)^c] = 16/78 P(B∪S)=1- 16/78 = 62/78 &lt;-- 1-P(B∪S)^c [P(B)+P(S) - P(B∩S)] ↔ P(B∩S) = P(B)+P(S)-P(B∪S) = 35/78 + 32/78 - 62/78 Team Home Away Total 2. Purchased food 120 40 160 Did not purchase food 60 30 90 Total 180 70 250 The table shows data that were collected from people who attended a certain high school basketball game. A person who attended the game will be selected at random. Which of the following correctly interprets mutually exclusive events represented by the table? A. Rooting for the home team and rooting for the away team B. Rooting for the home team and purchasing food during the game C. Rooting for the away team and purchasing food during the game D. Rooting for the home team and not purchasing food during the game E. Not rooting for the home team and not purchasing food during the game P(B∩S) = P(S) P(B|S) 3. A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at random to participate in the county chess tournament. What is the probability that Adam and Ella will be selected? A. 1/20 B. 1/10 C. 1/8 D. 1/7 E. 1/4 B 5x4 D A 2 E 20 4. Events D and E are independent, with P(D) = 0.6 and P(D and E) = 0.18. Which of the following is true? A. P(E) = 0.12 B. P(E) = 0.4 C. P(D or E) = 0.28 D. P(D or E) = 0.72 E. P(D or E) = 0.9 5. One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, and let B be the event that the selected student drives to school. If P(A ∩ B) = 0.08 and P(B | A) = 0.25, what is the probability that the selected student will be a student athlete? A. 0.02 B. 0.17 C. 0.32 D. 0.33 E. 3.13 6. Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appearing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6? A. 2/36 B. 3/36 C. 3/15 D. 2/9 E. 4/6 7. As a promotion, the first 50 customers who entered a certain store at a mall were asked to choose from one of two discounts. The first discount choice was 20% off all purchases made that day. The second discount choice was 10% off all purchases for the week. Of those who received the discounts, 28 chose the first discount and 22 chose the second discount. One customer will be selected at random from those who received a discount. Let F represent the event that the selected person chose the first discount, and let S represent the event that the selected person chose the second discount. Are F and S mutually exclusive events? A. Yes, because P(F∩S) = 0. B. Yes, because P(F∩S) = 0.12. C. Yes, because P(F∩S) = 1. D. No, because P(F∩S) = 0. E. No, because P(F ∩ S) = 1. 8. For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem. If one flight is selected at random from the airport in January, what is the probability that the flight selected will have at least one of the two types of delays? A. 0.065 B. 0.335 C. 0.350 D. 0.450 E. 0.665 9. Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. Of the 80 male students who were surveyed, 60 had brown eyes. If eye color and gender are independent, how many female students surveyed would be expected to have brown eyes? A. 5 B. 20 C. 30 D. 90 E. 100 10. The SC Electric Company has bid on two electrical wiring jobs. The owner of the company believes that • the probability of being awarded the first job (event A) is 0.75; • the probability of being awarded the second job (event B) is 0.5; and • the probability of being awarded both jobs (event (A and B)) is 0.375. If the owner's beliefs are correct, which of the following statements must be true concerning event A and event B? A. Event A and event B are mutually exclusive and are independent. B. Event A and event B are mutually exclusive and are not independent. C. Event A and event B are not mutually exclusive and are independent. D. Event A and event B are not mutually exclusive and are not independent. E. Event A and event B are not mutually exclusive, and independence cannot be determined. 11. For which of the following probability assignments are events A and B independent? A. P(A ∩ B^c) = 0.3, P(A ∩ B) = 0.12, and P(A^c ∩ B) = 0.4. B. P(A ∩ B^c) = 0.3, P(A ∩ B) = 0.3, and P(A^c ∩ B) = 0.3. C. P(A ∩ B^c) = 0.1, P(A ∩ B) = 0.1, and P(A^c ∩ B) = 0.4. D. P(A ∩ B^c) = 0.3, P(A ∩ B) = 0.0, and P(A^c ∩ B) = 0.2. E. P(A ∩ B^c) = 0.5, P(A ∩ B) = 0.1, and P(A^c ∩ B) = 0.4. 12. Ms. Tucker travels through two intersections with traffic lights as she drives to the market. The traffic lights operate independently. The probability that both lights will be red when she reaches them is 0.22. The probability that the first light will be red and the second light will not be red is 0.33. What is the probability that the second light will be red when she reaches it? A. 0.40 B. 0.45 C. 0.50 D. 0.55 E. 0.60 13. In a certain school, 17 percent of the students are enrolled in a psychology course, 28 percent are enrolled in a foreign language course, and 32 percent are enrolled in either a psychology course or a foreign language course or both. What is the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course? A. 0.45 B. 0.32 C. 0.20 D. 0.13 E. 0.05 14. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged during delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years? A. 0.05 B. 0.06 C. 0.10 D. 0.40 E. 0.50 15. A student is applying to two different agencies for scholarships. Based on the student's academic record, the probability that the student will be awarded a scholarship from Agency A is 0.55 and the probability that the student will be awarded a scholarship from Agency B is 0.40. Furthermore, if the student is awarded a scholarship from Agency A, the probability that the student will be awarded a scholarship from Agency B is 0.60. What is the probability that the student will be awarded at least one of the two scholarships? A. 0.60 B. 0.62 C. 0.71 D. 0.73 E. 0.95 2 Discrete Random Variables 1. The following table shows the probability distribution for the number of books a student typically buys at the annual book fair held at an elementary school. Number of Books 0 1 2 3 4 5 6 7 Probability 0.35 0.20 0.15 0.10 0.07 0.08 0.04 0.01 Let the random variable B represent the number of books a student buys at the next book fair. What is the expected value of B? A. 0 B. 1.00 C. 1.79 D. 3.50 E. 28 2. At a large regional collegiate women's swim meet, an official records the time it takes each swimmer to swim 100 meters for all swimmers who compete in only one stroke category. The following table shows the mean times and corresponding standard deviations for the collegiate women at the swim meet for each of the four stroke categories. Stroke Category Mean 100 meter Time Standard Deviation Backstroke 55.6 seconds 0.70 seconds Breaststroke 63.3 seconds 0.92 seconds Butterfly 54.4 seconds 0.94 seconds Freestyle 50.2 seconds 0.76 seconds For each of the 4 stroke categories, consider a random variable representing the time of a randomly selected swimmer in that category. What is the standard deviation of the sum of the 4 random variables? A. 0.83 seconds B. 1.67 seconds C. 2.80 seconds D. 3.32 seconds E. 3.76 seconds 3. A player pays $15 to play a game in which a chip is randomly selected from a bag of chips. The bag contains 10 red chips, 4 blue chips, and 6 yellow chips. The player wins $5 if a red chip is selected, $10 if a blue chip is selected, and $20 if a yellow chip is selected. Let the random variable X represent the amount won from the selection of the chip, and let the random variable W represent the total amount won, where W = X – 15. What is the mean of W? A. $10.50 B. $4.50 C. -$4.50 D. -$6.50 E. -$10.50 4. A city department of transportation studied traffic congestion on a certain highway. To encourage carpooling, the department will recommend a carpool lane if the average number of people in passenger cars on the highway is less than 2. The probability distribution of the number of people in passenger cars on the highway is shown in the table. Number of people 1 2 3 4 5 Probability 0.56 0.28 0.08 0.06 0.02 Based on the probability distribution, what is the mean number of people in passenger cars on the highway? A. 0.28 B. 0.56 C. 1.7 D. 2 E. 3 5. Every Thursday, Matt and Dave's Video Venture has "roll-the-dice" day. A customer may choose to roll two fair dice and rent a second movie for an amount (in cents) equal to the numbers uppermost on the dice, with the larger number first. Let X represent the amount paid for a second movie on roll-the-dice day. The expected value of X is $0.47 and the standard deviation of X is $0.15. If a customer rolls the dice and rents a second movie every Thursday for 30 consecutive weeks, what is the approximate probability that the total amount paid for these second movies will exceed $15.00? A. 0 B. 0.09 C. 0.14 D. 0.86 E. 0.91 6. The distribution of random variable R has mean 10 and standard deviation 4. The distribution of random variable S has mean 7 and standard deviation 3. If R and S are independent, what are the mean and standard deviation of the distribution of R – S? A. Mean 3 and standard deviation 1 B. Mean 3 and standard deviation 5 C. Mean 3 and standard deviation 7 D. Mean 17 and standard deviation 1 E. Mean 17 and standard deviation 5 7. At a certain bakery, the price of each doughnut is $1.50. Let the random variable D represent the number of doughnuts a typical customer purchases each day. The expected value and variance of the probability distribution of D are 2.6 doughnuts and 3.6 (doughnuts)2, respectively. Let the random variable P represent the price of the doughnuts that a typical customer purchases each day. Which of the following is the standard deviation, in dollars, of the probability distribution of P? A. 1.5(3.6) B. 1.5√3.6 C. √1.5(3.6) D. 1.5(2.6) E. 1.5√2.6 8. The XYZ Office Supplies Company sells calculators in bulk at wholesale prices, as well as individually at retail prices. The following tables are estimates for next year's sales. WHOLESALE SALES Number Sold 2,000 5,000 10,000 20,000 Probability 0.1 0.3 0.4 0.2 RETAIL SALES Number Sold 600 1,000 1,500 Probability 0.4 0.5 0.1 What profit does XYZ Office Supplies Company expect to make for the next year if the profit from each calculator sold is $20 at wholesale and $30 at retail? A. $10,590 B. $220,700 C. $264,750 D. $833,100 E. $1,002,500 9. In a certain game, a fair die is rolled and a player gains 20 points if the die shows a "6." If the die does not show a "6," the player loses 3 points. If the die were to be rolled 100 times, what would be the expected total gain or loss for the player? A. A gain of about 1,700 points B. A gain of about 583 points C. A gain of about 83 points D. A loss of about 250 points E. A loss of about 300 points 10. A box contains 10 tags, numbered 1 through 10, with a different number on each tag. A second box contains 8 tags, numbered 20 through 27, with a different number on each tag. One tag is drawn at random from each box. What is the expected value of the sum of the numbers on the two selected tags? A. 13.5 B. 14.5 C. 15.0 D. 27.0 E. 29.0 11. Let X represent the number on the face that lands up when a fair six-sided number cube is tossed. The expected value of X is 3.5, and the standard deviation of X is approximately 1.708. Two fair six-sided number cubes will be tossed, and the numbers appearing on the faces that land up will be added. Which of the following values is closest to the standard deviation of the resulting sum? A. 1.708 B. 1.848 C. 2.415 D. 3.416 E. 5.835 12. A company that makes fleece clothing uses fleece produced from two farms, Northern Farm and Western Farm. Let the random variable X represent the weight of fleece produced by a sheep from Northern Farm. The distribution of X has mean 14.1 pounds and standard deviation 1.3 pounds. Let the random variable Y represent the weight of fleece produced by a sheep from Western Farm. The distribution of Y has mean 6.7 pounds and standard deviation 0.5 pound. Assume X and Y are independent. Let W equal the total weight of fleece from 10 randomly selected sheep from Northern Farm and 15 randomly selected sheep from Western Farm. Which of the following is the standard deviation, in pounds, of W? A. 1.3 +0.5 B. √1.3^2 + 0.5^2 C. √10(1.3)^2 + 15(0.5)^2 D. √10^2(1.3)^2 + 15^2(0.5)^2 E. √(1.3^2/10) + (0.5^2/15) 3 The Normal Distribution 1. Two college roommates have each committed to donating to charity each week for the next year. The roommates' weekly incomes are independent of each other. Suppose the amount donated in a week by one roommate is approximately normal with mean $30 and standard deviation $10, and the amount donated in a week by the other roommate is approximately normal with mean $60 and standard deviation $20. Which of the following is closest to the expected number of weeks in a 52-week year that their combined donation will exceed $120? A. 0; the combined donation never exceeds $120 in a week B. 1 week C. 3 weeks D. 5 weeks E. 8 weeks 2. The distribution of random variable R has mean 10 and standard deviation 4. The distribution of random variable S has mean 7 and standard deviation 3. If R and S are independent, what are the mean and standard deviation of the distribution of R – S? A. Mean 3 and standard deviation 1 B. Mean 3 and standard deviation 5 C. Mean 3 and standard deviation 7 D. Mean 17 and standard deviation 1 E. Mean 17 and standard deviation 5 3. A summer resort rents rowboats to customers but does not allow more than four people to a boat. Each boat is designed to hold no more than 800 pounds. Suppose the distribution of adult males who rent boats, including their clothes and gear, is normal with a mean of 190 pounds and standard deviation of 10 pounds. If the weights of individual passengers are independent, what is the probability that a group of four adult male passengers will exceed the acceptable weight limit of 800 pounds? A. 0.023 B. 0.046 C. 0.159 D. 0.317 E. 0.977 4. Carly commutes to work, and her commute time is dependent on the weather. When the weather is good, the distribution of her commute times is approximately normal with mean 20 minutes and standard deviation 2 minutes. When the weather is not good, the distribution of her commute times is approximately normal with mean 30 minutes and standard deviation 4 minutes. Suppose the probability that the weather will be good tomorrow is 0.9. Which of the following is closest to the probability that Carly's commute time tomorrow will be greater than 25 minutes? A. 0.0056 B. 0.0894 C. 0.0950 D. 0.8055 E. 0.9006 5. Sean and Evan are college roommates who have part-time jobs as servers in restaurants. The distribution of Sean's weekly income is approximately normal with mean $225 and standard deviation $25. The distribution of Evan's weekly income is approximately normal with mean $240 and standard deviation $15. Assuming their weekly incomes are independent of each other, which of the following is closest to the probability that Sean will have a greater income than Evan in a randomly selected week? A. 0.067 B. 0.159 C. 0.227 D. 0.303 E. 0.354 6. A company ships gift baskets that contain apples and pears. The distributions of weight for the apples, the pears, and the baskets are each approximately normal. The mean and standard deviation for each distribution is shown in the table below. The weights of the items are assumed to be independent. Item Mean Standard Deviation Apple 4.72 ounces 0.20 ounce Pear 5.41 ounces 0.18 ounce Basket 13.25 ounces 1.88 ounces Let the random variable W represent the total weight of 4 apples, 6 pears, and 1 basket. Which of the following is closest to the standard deviation of W? A. 1.90 ounces B. 1.97 ounces C. 2.26 ounces D. 3.76 ounces E. 3.83 ounces 7. The Attila Barbell Company makes bars for weight lifting. The weights of the bars are independent and are normally distributed with a mean of 720 ounces (45 pounds) and a standard deviation of 4 ounces. The bars are shipped 10 in a box to the retailers. The weights of the empty boxes are normally distributed with a mean of 320 ounces and a standard deviation of 8 ounces. The weights of the boxes filled with 10 bars are expected to be normally distributed with a mean of 7,520 ounces and a standard deviation of A. √12 ounces B. √80 ounces C. √224 ounces D. 48 ounces E. √1,664 ounces 8. The continuous random variable N has a normal distribution with mean 7.5 and standard deviation 2.5. For which of the following is the probability equal to 0? A. P(N = 8) B. P(N > 8) C. P(N &lt; 8) D. P(7 &lt; N &lt; 8) E. P(N &lt; 7) or P(N > 8) 4 Binomial and Geometric Distributions 1. A large store has a customer service department where customers can go to ask for help with store-related issues. According to store records, approximately 1/4 of all customers who go to the service department ask for help finding an item. Assume the reason each customer goes to the service department is independent from customer to customer. Based on the approximation, what is the probability that at least 1 of the next 4 customers who go to the service department will ask for help finding an item? A. 4(1/4) B. 1-(1/4)^4 C. 1-(3/4)^4 D. 4(1/4)(3/4)^3 E. (1/4)(1/4)(1/4)(1/4) 2. Based on his past record, Luke, an archer for a college archery team, has a probability of 0.90 of hitting the inner ring of the target with a shot of the arrow. Assume that in one practice Luke will attempt 5 shots of the arrow and that each shot is independent from the others. Let the random variable X represent the number of times he hits the inner ring of the target in 5 attempts. What is the probability that the number of times Luke will hit the inner ring of the target out of the 5 attempts is less than the mean of X? A. 0.40951 B. 0.50000 C. 0.59049 D. 0.91854 E. 0.99144 3. Mateo plays on his school basketball team. From past history, he knows that his probability of making a basket on a free throw is 0.8. Suppose he wants to create a simulation using random numbers to estimate the probability of making at least 3 baskets on his next 5 free throw attempts. Which of the following assignments of the digits 0 to 9 could be used for the simulation? A. Let the even digits represent making a basket and the odd digits represent not making a basket. B. Let the digits 0 and 1 represent making a basket and the digits from 2 to 9 represent not making a basket. C. Let the digits from 0 to 3 represent making a basket and the digits from 4 to 9 represent not making a basket. D. Let the digits from 0 to 6 represent making a basket and the digits from 7 to 9 represent not making a basket. E. Let the digits from 0 to 7 represent making a basket and the digits 8 and 9 represent not making a basket. 4. According to a recent survey, 31 percent of the residents of a certain state who are age 25 years or older have a bachelor's degree. A random sample of 50 residents of the state, age 25 years or older, will be selected. Let the random variable B represent the number in the sample who have a bachelor's degree. What is the probability that B will equal 40? A. (50 choose 40) (0.31)^40 (0.69)^10 B. (50 choose 10) (0.69)^40 (0.31)^10 C. (50 choose 10) (0.31)^40 (0.69)^10 D. (50 choose 10) (0.69)^40 (0.31)^10 E. 40(0.31)^50 5. A blind taste test will be conducted with 9 volunteers to determine whether people can taste a difference between bottled water and tap water. Each participant will taste the water from two different glasses and then identify which glass he or she thinks contains the tap water. Assuming that people cannot taste a difference between bottled water and tap water, what is the probability that at least 8 of the 9 participants will correctly identify the tap water? A. 0.0020 B. 0.0195 C. 0.8889 D. 0.9805 E. 0.9980 6. In a certain board game, a player rolls two fair six-sided dice until the player rolls doubles (where the value on each die is the same). The probability of rolling doubles with one roll of two fair six-sided dice is 1/6. What is the probability that it takes three rolls until the player rolls doubles? A. (1/6)^3 B. (5/6)^3 C. (1/6)(5/6)^3 D. (1/6)(5/6)^2 E. (5/6)(1/6)^2 7. A company that ships crystal bowls claims that bowls arrive undamaged in 95 percent of the shipments. Let the random variable G represent the number of shipments with undamaged bowls in 25 randomly selected shipments. Random variable G follows a binomial distribution with a mean of 23.75 shipments and a standard deviation of approximately 1.09 shipments. Which of the following is the best interpretation of the mean? A. Every shipment of 25 bowls will have 23.75 undamaged bowls. B. Every shipment of 25 bowls will have 23.75 damaged bowls. C. On average, the company receives 23.75 shipments before receiving the first shipment with a damaged bowl. D. For all possible shipments of size 25, the average number of damaged shipments is equal to 23.75. E. For all possible shipments of size 25, the average number of undamaged shipments is equal to 23.75. 8. The transaction history at an electronic goods store indicates that 21 percent of customers purchase the extended warranty when they buy an eligible item. Suppose customers who buy eligible items are chosen at random, one at a time, until one is found who purchased the extended warranty. Let the random variable X represent the number of customers it takes to find one who purchased the extended warranty. Assume customers' decisions on whether to purchase the extended warranty are independent. Which of the following is closest to the probability that X > 3? A. 0.131 B. 0.390 C. 0.493 D. 0.507 E. 0.624 9. According to a recent survey, 81 percent of adults in a certain state have graduated from high school. If 15 adults from the state are selected at random, what is the probability that 5 of them have not graduated from high school? A. (20 choose 15) (0.19)^15 (0.81)^5 B. (15 choose 5) (0.19)^15 (0.81)^15 C. (15 choose 10) (0.81)^5 (0.19)^10 D. (15 choose 5) (0.19)^5 (0.81)^10 E. (15 choose 5) (0.81)^5 (0.19)^10 10. A recent study reported that 45 percent of adults in the United States now get all their news online. A random sample of 8 adults in the United States will be selected. What is the probability that 6 of the selected adults get all their news online? A. (8 choose 2) (0.45)^8 (0.55)^2 B. (8 choose 6) (0.45)^6 (0.55)^2 C. (8 choose 2) (0.45)^2 (0.55)^8 D. (8 choose 6) (0.45)^6 (0.55)^2 E. (8 choose 8) (0.45)^8 (0.55)^6 5 Sampling Distributions 1. For which of the following conditions is it not appropriate to assume that the sampling distribution of the sample mean is approximately normal? A. A random sample of 8 taken from a normally distributed population B. A random sample of 50 taken from a normally distributed population C. A random sample of 10 taken from a population distribution that is skewed to the right D. A random sample of 75 taken from a population distribution that is skewed to the left E. A random sample of 100 taken from a population that is uniform 2. Researchers working for a certain airline are investigating the weight of carry-on bags. The researchers will use the mean weight of a random sample of 800 carry-on bags to estimate the mean weight of all carry-on bags for the airline. Which of the following best describes the effect on the bias and the variance of the estimator if the researchers increase the sample size to 1,300? A. The bias will decrease and the variance will remain the same. B. The bias will increase and the variance will remain the same. C. The bias will remain the same and the variance will decrease. D. The bias will remain the same and the variance will increase. E. The bias will decrease and the variance will decrease. 3. A bag contains chips of which 27.5 percent are blue. A random sample of 5 chips will be selected one at a time and with replacement. What are the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5? A. The mean is 5(0.275), and the standard deviation is √5(0.275)(0.725). B. The mean is 0.275, and the standard deviation is √(0.275)(0.725)/5 D. The mean is 27.5, and the standard deviation is √5(27.5)(72.5). E. The mean is 27.5, and the standard deviation is √(27.5)(72.5)/5 4. In two common species of flowers, A and B, the proportions of flowers that are blue are pa and pь, respectively. Suppose that independent random samples of 50 species-A flowers and 100 species-B flowers are selected. Let pa be the sample proportion of blue species-A flowers and it be the sample proportion of blue species-B flowers. What is the mean of the sampling distribution of pa - pь? A. pa - pb B. pa/50 - pb/100 C. pa - pb D. pa(1-pa)/50 + pb(1-pb)/100 E. √[pa(1-pa)/50 + pb(1-pb)/100] 5. Suppose the variance in trunk diameter of the giant sequoia tree species is 15.7 m², while the variance in trunk diameter of the California redwood tree species is 10.6 m². Let x1 represent the average trunk diameter of four randomly sampled giant sequoia trees, and let x2 represent the average trunk diameter of three randomly sampled California redwood trees. If the random sampling is done with replacement, what is the standard deviation (x1 - x2) of the sampling distribution of the difference in sample means x1 - x2? A. √(15.7 - 10.6)/4 B. √(15.7 - 10.6)/3 C. √(15.7/4 + 10.6/3) D. √(15.7 + 10.6) E. (15.7/4 + 10.6/3) 6. A manufacturer of cell phone batteries claims that the average number of recharge cycles for its batteries is 400. A consumer group will obtain a random sample of 100 of the manufacturer's batteries and will calculate the mean number of recharge cycles. Which of the following statements is justified by the central limit theorem? A. The distribution of the number of recharge cycles for the sample is approximately normal because the population mean of 400 is greater than 30. B. The distribution of the number of recharge cycles for the sample is approximately normal because the sample size of 100 is greater than 30. C. The distribution of the number of recharge cycles for the population is approximately normal because the sample size of 100 is greater than 30. D. The distribution of the sample means of the number of recharge cycles is approximately normal because the sample size of 100 is greater than 30. E. The distribution of the sample means of the number of recharge cycles is approximately normal because the population mean of 400 is greater than 30. 7. The normal curve shown represents the sampling distribution of a sample mean for sample size n = 25, selected at random from a population with standard deviation σx. (Refer to the image in the original prompt where a normal curve is shown with an x-axis span.) Which of the following is the best estimate of the standard deviation of the population, σx? A. 3 B. 6 C. 15 D. 30 E. 75 8. Based on records kept at a gas station, the distribution of gallons of gas purchased by customers is skewed to the right with mean 10 gallons and standard deviation 4 gallons. A random sample of 64 customer receipts was selected, and the sample mean number of gallons was recorded. Suppose the process of selecting a random sample of 64 receipts and recording the sample mean number of gallons was repeated for a total of 100 samples. Which of the following is the best description of a dotplot created from the 100 sample means? A. The dotplot is skewed to the right with mean 10 gallons and standard deviation 4 gallons. B. The dotplot is skewed to the right with mean 10 gallons and standard deviation 0.5 gallon. C. The dotplot is skewed to the right with mean 10 gallons and standard deviation 0.4 gallon. D. The dotplot is approximately normal with mean 10 gallons and standard deviation 0.5 gallon. E. The dotplot is approximately normal with mean 10 gallons and standard deviation 0.4 gallon. 9. The director of a marketing department wants to estimate the proportion of people who purchase a certain product online. The director originally planned to obtain a random sample of 2,500 people who purchased the product. However, because of budget concerns, the sample size will be reduced to 1,500 people. Which of the following describes the effect of reducing the number of people in the sample? A. The variance of the sample will increase. B. The variance of the population will decrease. C. The variance of the sampling distribution of the estimator will increase. D. The variance of the sampling distribution of the estimator will decrease. E. The variance of the sampling distribution of the estimator will remain the same. 10. The graph shows the population distribution of random variable X with mean 85 and standard deviation 18. (The graph shows a skewed distribution). Which of the following graphs is a sampling distribution of the sample mean x-bar for samples of size 40 taken from the population? A. A graph similar to the population (skewed). B. A graph slightly less skewed. C. An approximately normal distribution centered at 85 with smaller spread. D. An approximately normal distribution centered at 85 with larger spread. E. A uniform distribution. (Note: Based on CLT, for n = 40, the sampling distribution should be approximately normal). 11. Two different drugs, X and Y, are currently in use to treat a certain condition. About 7 percent of the people using either drug experience side effects. A random sample of 75 people using drug X and a random sample of 150 people using drug Y are selected. The proportion of people in each sample who experience side effects is recorded. Are the sample sizes large enough to assume that the sampling distribution of the difference in sample proportions is approximately normal? A. Yes. Both sample sizes are large enough. B. No. The sample size for drug X is large enough, but the sample size for drug Y is not. C. No. The sample size for drug Y is large enough, but the sample size for drug X is not. D. No. Neither sample size is large enough. E. There is not enough information provided to determine whether the sampling distribution is approximately normal. 12. A recent survey concluded that the proportion of American teenagers who have a cell phone is 0.27. The true population proportion of American teenagers who have a cell phone is 0.29. For samples of size 1,000 that are selected at random from this population, what are the mean and standard deviation, respectively, for the sampling distribution of the sample proportion of American teenagers who have a cell phone? A. 0.27, √(1000)(0.27)(0.73) B. 0.27, √(0.29)(0.71) C. 0.27, √(0.27)(0.73)/1000 D. 0.29, √(0.29)(0.71)/1000 E. 0.29, √(1000)(0.29)(0.71) 13. A reading specialist wanted to estimate the mean word length, in number of letters, for an elementary school history textbook. The specialist took repeated random samples of size 100 words and estimated the mean and standard deviation of the sampling distribution to be 4.9 letters and 0.15 letter, respectively. Based on the estimates for the sampling distribution, which of the following provides the best estimates of the population parameters? A. Mean 4.9 letters and standard deviation 0.015 letter B. Mean 4.9 letters and standard deviation 0.15 letter C. Mean 4.9 letters and standard deviation 1.5 letters D. Mean 0.49 letter and standard deviation 0.15 letter E. Mean 49 letters and standard deviation 15 letters
&lt;/div></description></item><item><title>Note Update: Continuous Random Variables: Uniform and Normal Distributions</title><link>https://ap-stat.zhtek.org/notes/note-dec-22-2025/</link><pubDate>Wed, 24 Dec 2025 04:51:40 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/note-dec-22-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/note-dec-22-2025.webp" alt="Featured image of post Note Update: Continuous Random Variables: Uniform and Normal Distributions" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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Continuous R.V. Pistribution. X has infinite possible ontiome =0 D. P(X=K) -0. 2).只有取一个范围才 有根无率 Special distributions for Continuous R.V. 1) uniform distribution. area=1. a kr 云记 proportion area probability perientage/ percentile PCK,≤x≤1) K2-K b-a- b-a. E(X)= bu 2 Std (x) = b_a =(X)P+S - dcz 2) normal distribution. 有其它,求area.用normalcdf. 有avea,求其它,用inu Norm. •
&lt;/div></description></item><item><title>Note Update: AP Statistics: Probability Rules Practice Problems</title><link>https://ap-stat.zhtek.org/notes/temp/</link><pubDate>Wed, 24 Dec 2025 04:51:25 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/temp/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/temp.webp" alt="Featured image of post Note Update: AP Statistics: Probability Rules Practice Problems" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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AP StatisticsUnit 4: Probability RulesPage 11. A fair six-sided die is rolled twice. What is the probability that thesum of the two rolls is 5?A. 118B.12C.1D.6Ε. 536AP StatisticsUnit 4: Probability RulesPage 22. In a large high school, 40% of students take a Music class, 30% ofstudents take an Art class, and 10% of students take both Music andArt. If a student is selected at random, what is the probability thatthey take at least one of these classes?A. 0.10Β. 0.50C. 0.60D. 0.70Ε. 0.80Page 2AP StatisticsUnit 4: Probability RulesPage 33. Events A and B are independent. If P(A) = 0.4 and P(B) = 0.5,which of the following statements is true?A. P(A ∩ B) = 0B. P(AUB) = 0.9C. P(A|B) = 0.4D. P(A|B) = 0.5E. P(A ∩ B) = 0.9Page 3AP StatisticsUnit 4: Probability RulesPage 44. A bag contains red, blue, and green marbles. The probability of draw-ing a red marble is 0.35 and the probability of drawing a blue marbleis 0.25. Events "Red" and "Blue" are mutually exclusive. What is theprobability of drawing a marble that is neither red nor blue?A. 0.10B. 0.40C. 0.50D. 0.60Ε. 0.875Page 4AP StatisticsUnit 4: Probability RulesPage 55. Let P(A) = 0.6, P(B) = 0.5, and P(AUB) = 0.8. A Venn diagram isconstructed to model these probabilities. What is the value of P(A∩B)?A. 0.1B. 0.2C. 0.3D. 0.4Ε. 1.1Page 5AP StatisticsUnit 4: Probability RulesPage 66. A medical test for a rare disease has a 95% sensitivity (it correctlyidentifies the disease 95% of the time given the person has it) and a90% specificity (it correctly identifies healthy people 90% of the time).Suppose 2% of the population actually has the disease. If a person ischosen at random and tested, what is the probability that they testpositive?A. 0.019Β. 0.098С. 0.117D. 0.855Ε. 0.950Page 6AP StatisticsUnit 4: Probability RulesPage 77. At a local coffee shop, 60% of customers order coffee, 30% order apastry, and 20% order both coffee and a pastry. Given that a randomlyselected customer ordered coffee, what is the probability that they alsoordered a pastry?A.5B.3C.2D.Ε.2-3 5-6Page 7AP StatisticsUnit 4: Probability RulesPage 88. A basketball player makes free throws with a probability of 0.8. As-sume each shot is independent. If the player shoots 3 free throws, whatis the probability that she misses at least one?A. 0.23Β. 1 – 0.83С. 1 -0.23D. 0.8 × 0.2E. 3 × 0.82 × 0.2Page 8
&lt;/div></description></item><item><title>Note Update: AP Statistics Review: Probability, Random Variables, and Sampling Distributions</title><link>https://ap-stat.zhtek.org/notes/temp-2/</link><pubDate>Wed, 24 Dec 2025 04:51:03 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/temp-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/temp-2.webp" alt="Featured image of post Note Update: AP Statistics Review: Probability, Random Variables, and Sampling Distributions" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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AP Statistics Practice Exam Topic-Based Review 2025 1 Probability: General Rules, Independence, and Conditional Prob- ability 1. A high school science teacher has 78 students. Of those students, 35 are in the band and 32 are on a sports team. There are 16 students who are not in the band or on a sports team. One student from the 78 students will be selected at random. Let event B represent the event of selecting a student in the band, and let event S represent the event of selecting a student on a sports team. Are B and S mutually exclusive events? A. No, because P(BnS) = . 5 78. B. No, because P(BnS) = 48 78. C. No, because P(BnS) = 62 78 D. Yes, because P(BnS) = . 5 78. E. Yes, because P(BnS) 62 78. Team Home Away Total 2. Purchased food 120 40 160 Did not purchase food 60 30 90 Total 180 70 250 The table shows data that were collected from people who attended a certain high school basketball game. A person who attended the game will be selected at random. Which of the following correctly interprets mutually exclusive events represented by the table? A. Rooting for the home team and rooting for the away team B. Rooting for the home team and purchasing food during the game C. Rooting for the away team and purchasing food during the game D. Rooting for the home team and not purchasing food during the game E. Not rooting for the home team and not purchasing food during the game 3. A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at random to participate in the county chess tournament. What is the probability that Adam and Ella will be selected? A. 20 B. 1/20 1/10 1/8 17 Ε. 4. Events D and E are independent, with P(D) = 0.6 and P(D and E) = 0.18. Which of the following is true? 1 A. P(E) = 0.12 B. P(E) = 0.4 C. P(D or E) = 0.28 D. P(D or E) = 0.72 E. P(D or E) = 0.9 5. One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, and let B be the event that the selected student drives to school. If P(A∩B) = 0.08 and P(B|A) = 0.25, what is the probability that the selected student will be a student athlete? A. 0.02 B. 0.17 C. 0.32 D. 0.33 Ε. 3.13 6. Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appearing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6? A. 2/36 Β. 3/36 C. 3/15 D. 2/9 Ε. 4/6 7. As a promotion, the first 50 customers who entered a certain store at a mall were asked to choose from one of two discounts. The first discount choice was 20% off all purchases made that day. The second discount choice was 10% off all purchases for the week. Of those who received the discounts, 28 chose the first discount and 22 chose the second discount. One customer will be selected at random from those who received a discount. Let F represent the event that the selected person chose the first discount, and let S represent the event that the selected person chose the second discount. Are F and S mutually exclusive events? A. Yes, because P(F∩S) = 0. B. Yes, because P(F∩S) = 0.12. C. Yes, because P(F∩S) = 1. D. No, because P(F∩S) = 0. E. No, because P(F∩S) = 1. 8. For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem. If one flight is selected at random from the airport in January, what is the probability that the flight selected will have at least one of the two types of delays? A. 0.065 B. 0.335 C. 0.350 D. 0.450 Page 2 Ε. 0.665 9. Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. Of the 80 male students who were surveyed, 60 had brown eyes. If eye color and gender are independent, how many female students surveyed would be expected to have brown eyes? A. 5 B. 20 C. 30 D. 90 Ε. 100 10. The SC Electric Company has bid on two electrical wiring jobs. The owner of the company believes that • the probability of being awarded the first job (event A) is 0.75; • the probability of being awarded the second job (event B) is 0.5; and • the probability of being awarded both jobs (event (A and B)) is 0.375. If the owner's beliefs are correct, which of the following statements must be true concerning event A and event B? A. Event A and event B are mutually exclusive and are independent. B. Event A and event B are mutually exclusive and are not independent. C. Event A and event B are not mutually exclusive and are independent. D. Event A and event B are not mutually exclusive and are not independent. E. Event A and event B are not mutually exclusive, and independence cannot be determined. 11. For which of the following probability assignments are events A and B independent? A. P(A∩BC) = 0.3, P(A ∩ B) = 0.12, and P(A ∩ B) = 0.4. B. P(A ∩ B) = 0.3, P(A ∩ B) = 0.3, and P(A ∩ B) = 0.3. C. P(A ∩ B) = 0.1, P(A ∩ B) = 0.1, and P(A ∩ B) = 0.4. D. P(A ∩ B) = 0.3, P(A ∩ B) = 0.0, and P(A ∩ B) = 0.2. E. P(A∩BC) = 0.5, P(A ∩ B) = 0.1, and P(A ∩ B) = 0.4. 12. Ms. Tucker travels through two intersections with traffic lights as she drives to the market. The traffic lights operate independently. The probability that both lights will be red when she reaches them is 0.22. The probability that the first light will be red and the second light will not be red is 0.33. What is the probability that the second light will be red when she reaches it? A. 0.40 B. 0.45 C. 0.50 D. 0.55 Ε. 0.60 13. In a certain school, 17 percent of the students are enrolled in a psychology course, 28 percent are enrolled in a foreign language course, and 32 percent are enrolled in either a psychology course or a foreign language course or both. What is the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course? A. 0.45 B. 0.32 C. 0.20 Page 3 D. 0.13 Ε. 0.05 14. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged during delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years? A. 0.05 B. 0.06 C. 0.10 D. 0.40 Ε. 0.50 15. A student is applying to two different agencies for scholarships. Based on the student's academic record, the probability that the student will be awarded a scholarship from Agency A is 0.55 and the probability that the student will be awarded a scholarship from Agency B is 0.40. Furthermore, if the student is awarded a scholarship from Agency A, the probability that the student will be awarded a scholarship from Agency B is 0.60. What is the probability that the student will be awarded at least one of the two scholarships? A. 0.60 B. 0.62 C. 0.71 D. 0.73 Ε. 0.95 2 Discrete Random Variables 1. The following table shows the probability distribution for the number of books a student typically buys at the annual book fair held at an elementary school. Number of Books 0 1 2 3 4 5 6 7 Probability 0.35 0.20 0.15 0.10 0.07 0.08 0.04 0.01 Let the random variable B represent the number of books a student buys at the next book fair. What is the expected value of B? A. 0 B. 1.00 C. 1.79 D. 3.50 Ε. 28 2. At a large regional collegiate women's swim meet, an official records the time it takes each swimmer to swim 100 meters for all swimmers who compete in only one stroke category. The following table shows the mean times and corresponding standard deviations for the collegiate women at the swim meet for each of the four stroke categories. Stroke Category Mean 100 meter Time Standard Deviation Backstroke 55.6 seconds Breaststroke 63.3 seconds Butterfly 54.4 seconds Freestyle 50.2 seconds Page 4 0.70 seconds 0.92 seconds 0.94 seconds 0.76 seconds For each of the 4 stroke categories, consider a random variable representing the time of a randomly selected swimmer in that category. What is the standard deviation of the sum of the 4 random variables? A. 0.83 seconds B. 1.67 seconds C. 2.80 seconds D. 3.32 seconds E. 3.76 seconds 3. A player pays $15 to play a game in which a chip is randomly selected from a bag of chips. The bag contains 10 red chips, 4 blue chips, and 6 yellow chips. The player wins $5 if a red chip is selected, $10 if a blue chip is selected, and $20 if a yellow chip is selected. Let the random variable X represent the amount won from the selection of the chip, and let the random variable W represent the total amount won, where W = X – 15. What is the mean of W? A. $10.50 Β. $4.50 C. -$4.50 D. -$6.50 Ε. -$10.50 4. A city department of transportation studied traffic congestion on a certain highway. To encourage carpooling, the department will recommend a carpool lane if the average number of people in passenger cars on the highway is less than 2. The probability distribution of the number of people in passenger cars on the highway is shown in the table. 3 4 5 0.56 0.28 0.08 0.06 0.02 Number of people 1 2 Probability Based on the probability distribution, what is the mean number of people in passenger cars on the highway? A. 0.28 B. 0.56 C. 1.7 D. 2 E. 3 5. Every Thursday, Matt and Dave's Video Venture has
&lt;/div></description></item><item><title>Note Update: Random Variables, Binomial, and Geometric Distributions</title><link>https://ap-stat.zhtek.org/notes/binomial/</link><pubDate>Wed, 24 Dec 2025 04:49:23 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/binomial/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/binomial.webp" alt="Featured image of post Note Update: Random Variables, Binomial, and Geometric Distributions" />&lt;p>&lt;strong>Class:&lt;/strong> AP1 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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Prib. of events. et PCA)Prob. of complex events. eg.P(AMB)Random Variable.CategoricalX is the color of the studentthart enters the door nextX=Red} {X=Blue}Quantitatives Generic Distribution.Special Distribution.Generic Distribution.X023P(X=1)020.3 0.1 0.4Pcx&lt;1) =Area (ΣΧΕΣ)Area (S)0.240.3= 0.5Similar to categorical variable da proud of•everes,Special Distribution.discrete.离散Binomial distribution{Geometric distributionContinuous is normal连续 1 uniformeg 1.HHHHTHHHTHTHHITHHT. VTVITHHT33 coin toss.THT ✓TTH Vexactly I head.Tㅜ.ㅜㅜPL1 head)=3个total#ofoutomesBinomial Settings (Remember!!!)1). fixed number of trials n2) only.Sucess2 outromes each trialor failure.define yourself.3). fixed sucess prob. P.4). independent trials.X represent the number of sucess in n.4. trialsBinomial formula. غاBinomial. PDF...PDFnKn-kP(XK)Keg2: P(X=2) = 50.2 (1-0.2)3て271is(2)=(5 = 21/05/201nK=2!(5-2)!n=n!k!(n-k)!Binomial CDF.P(x≤k) = P(X=0) + P(X=1) + ··· +P(X=K)in, 5 prob. of successX ~ Binom (n, PR.V服从二项分布for each trial.max trialsE(X) = Mx = np↑expectedValue↓mean ofXStd(x) = 6x = Jupcr-p>↑std. of X.当P>0.5.x symmetric当up10, nc1-p)210时. X→Binom > Normalskew to the righ0当P→1時・且M(1-p)&lt;10畔、右裁断.Skew to the left(NX~ Geometric C几何分布X是多次实验,第一次成功的序数。Mit SP(X=k)=(1-p)*1 P &lt;PDF.{・PCX÷K) = P(X=1)+P(X=2).... + P(X=K)..first, until.(X) = std(x)=√↑PExpected value1-PP2(ouly skew to right
&lt;/div></description></item><item><title>Note Update: Special Probability Distributions: Discrete and Continuous</title><link>https://ap-stat.zhtek.org/notes/note-dec-19-2025/</link><pubDate>Wed, 24 Dec 2025 04:49:04 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/note-dec-19-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/note-dec-19-2025.webp" alt="Featured image of post Note Update: Special Probability Distributions: Discrete and Continuous" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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Special distributions for Quantitative R.V. Discrete R.V. { Binomial Geometric } Continuous. R.V. { Uniform Normal } PPF? CDF? E(X)?: Std(X)? P(X=K)=? P(X&lt;=K)=? shape: Skewness? Continuous R.V. PDF is meaningless. 1) PDF of continuous RV the height of the curve of corresponding point. P(X=k)=0. 2) the prob. of any given X=k, P(X=k) is Zero. Binomial: (1) definition of X: number of trials that succeeded in n trials. Geometric: (1) definition of X: the order of first success in a series of trials. Binomial Setting difference: total number of trials n. E(X)=Σx_i p_i. Std(X) = sqrt(Σ(x_i-μ)^2 p_i). Binomial: E(X)=μx = np. Std(X) = σx = sqrt(np(1-p)). 当np>10丑n(1-p)>10时. ・当np&lt;10且P>0. Geometric: E(X)=μx = 1/p. Std(X) = sqrt((1-p)/p^2). 永远. 当n(1-p)&lt;10旦P→1时.
&lt;/div></description></item><item><title>Note Update: Continuous Random Variables: Distributions and Linear Transformations</title><link>https://ap-stat.zhtek.org/notes/note-dec-23-2025/</link><pubDate>Wed, 24 Dec 2025 04:48:35 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/note-dec-23-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/note-dec-23-2025.webp" alt="Featured image of post Note Update: Continuous Random Variables: Distributions and Linear Transformations" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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Continuous R. V. distribution.1. PDF of any continuous R. V. is probability density functionmeaningless. it's not a probabilityPDF(X=k).for anycontinuous R.V. P(X=k) = 0 only P(a≤X≤b) is a prob.2. P(a≤X≤b) ⇒ CDFCumulative distribution functionFor discrete R.V. PDF is prob.i.e. P(X=k)>0For continuous R.V. PDF is not probability. P(X=k) = 0.Special continuous R.V. distribution.1) uniform distribution X~ Uniform (a, b)Area=11/(b-a)abP(i≤X≤j) = (j-i)/(b-a).E(X)= (a+b)/2.std(x)=(b-a)/√122) normal distribution X ~ Norm (μx, σx)bell-shapeddensity curveSymmetriclower: aP(a≤X≤b) = normalcdf(lower: a, upper: b, μ: μx, σ: σx)μ, σ is a given parameter.one R.V.E(X±a) = E(X) ±a.E(kX)= kE(X).E(kX±a) = kE(X) ±a.Two R.V.E(X±Y) = E(X) ±E(Y).no condition.E(aX±bY±c)= aE(X) ±bE(Y) ±c.E(aX±bY±cZ±d) = aE(X) ±bE(Y) ±cE(Z) ±d.std (aX) = √a Std(X).Std (X+b)= Std(X)Std (aX+b) = √a Std(X).std (X ± Y) = √std²(X) + std²(Y)std(X±Y±Z) = √std²(X) + Std²(Y) + Std²(Z)Std (aX+bY+c) = √(a Std²(X) + b Std²(Y))
&lt;/div></description></item><item><title>Note Update: Central Limit Theorem and Sampling Distributions</title><link>https://ap-stat.zhtek.org/notes/note-dec-24-2025/</link><pubDate>Wed, 24 Dec 2025 04:47:57 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/note-dec-24-2025/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/note-dec-24-2025.webp" alt="Featured image of post Note Update: Central Limit Theorem and Sampling Distributions" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unit 5 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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X is a random variable. With any distribution. Central limit theorem The sum of X (many many independent and identically distributed X) will become normal as the number of X goes larger. rule of thumb: when n>=30 the sum of X is already close to normal. -> 记. Sampling distribution: distribution of $\bar{X}$, $\hat{P}$ For $\bar{X}$ sample mean. 1) assume sample size $n \geq 30$. 2) assume sample size $n &lt; 0.1N$
&lt;/div></description></item><item><title>Note Update: Probability Rules, Discrete and Normal Random Variables, Binomial, Geometric, and Sampling Distributions</title><link>https://ap-stat.zhtek.org/notes/prob-2-2/</link><pubDate>Wed, 24 Dec 2025 04:47:42 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/prob-2-2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/prob-2-2.webp" alt="Featured image of post Note Update: Probability Rules, Discrete and Normal Random Variables, Binomial, Geometric, and Sampling Distributions" />&lt;p>&lt;strong>Class:&lt;/strong> AP3 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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1 Probability: General Rules, Independence, and Conditional Probability
1. A high school science teacher has 78 students. Of those students, 35 are in the band and 32 are on a sports team. There are 16 students who are not in the band or on a sports team. One student from the 78 students will be selected at random. Let event B represent the event of selecting a student in the band, and let event S represent the event of selecting a student on a sports team. Are B and S mutually exclusive events? A. No, because P(B∩S) = 5/78. B. No, because P(B ∩S) = 48/78. C. No, because P(B ∩S) = 62/78 D. Yes, because P(B∩S) = 5/78 E. Yes, because P(B∩S) = 62/78. Page 2
Team Home Away Total 2. Purchased food 120 40 160 Did not purchase food 60 30 90 Total 180 70 250 The table shows data that were collected from people who attended a certain high school basketball game. A person who attended the game will be selected at random. Which of the following correctly interprets mutually exclusive events represented by the table? A. Rooting for the home team and rooting for the away team B. Rooting for the home team and purchasing food during the game C. Rooting for the away team and purchasing food during the game D. Rooting for the home team and not purchasing food during the game E. Not rooting for the home team and not purchasing food during the game Page 2
3. A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at random to participate in the county chess tournament. What is the probability that Adam and Ella will be selected? A. 1/20 B. 1/10 C. 1/8 D. 1/7 E. 1/4 Page 4
4. Events D and E are independent, with P(D) = 0.6 and P(D and E) = 0.18. Which of the following is true? A. P(E) = 0.12 B. P(E) = 0.4 C. P(D or E) = 0.28 D. P(D or E) = 0.72 E. P(D or E) = 0.9 Page 5
5. One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, and let B be the event that the selected student drives to school. If P(A ∩ B) = 0.08 and P(B | A) = 0.25, what is the probability that the selected student will be a student athlete? A. 0.02 B. 0.17 C. 0.32 D. 0.33 E. 3.13 Page 6
6. Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appearing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6? A. 2/36 B. 3/36 C. 3/15 D. 2/9 E. 4/6 Page 7
7. As a promotion, the first 50 customers who entered a certain store at a mall were asked to choose from one of two discounts. The first discount choice was 20% off all purchases made that day. The second discount choice was 10% off all purchases for the week. Of those who received the discounts, 28 chose the first discount and 22 chose the second discount. One customer will be selected at random from those who received a discount. Let F represent the event that the selected person chose the first discount, and let S represent the event that the selected person chose the second discount. Are F and S mutually exclusive events? A. Yes, because P(F∩S) = 0. B. Yes, because P(F∩S) = 0.12. C. Yes, because P(F∩S) = 1. D. No, because P(F∩S) = 0. E. No, because P(F ∩ S) = 1. Page 8
8. For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem. If one flight is selected at random from the airport in January, what is the probability that the flight selected will have at least one of the two types of delays? A. 0.065 B. 0.335 C. 0.350 D. 0.450 E. 0.665 Page 0
9. Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. Of the 80 male students who were surveyed, 60 had brown eyes. If eye color and gender are independent, how many female students surveyed would be expected to have brown eyes? A. 5 B. 20 C. 30 D. 90 E. 100 Page 10
10. The SC Electric Company has bid on two electrical wiring jobs. The owner of the company believes that • the probability of being awarded the first job (event A) is 0.75; • the probability of being awarded the second job (event B) is 0.5; and • the probability of being awarded both jobs (event (A and B)) is 0.375. If the owner's beliefs are correct, which of the following statements must be true concerning event A and event B? A. Event A and event B are mutually exclusive and are independent. B. Event A and event B are mutually exclusive and are not independent. C. Event A and event B are not mutually exclusive and are independent. D. Event A and event B are not mutually exclusive and are not independent. E. Event A and event B are not mutually exclusive, and independence cannot be determined. Poco 11
11. For which of the following probability assignments are events A and B independent? A. P(A ∩ B) = 0.3, P(A ∩ B) = 0.12, and P(A∩ B) = 0.4. B. P(A ∩ Bᶜ) = 0.3, P(A ∩ B) = 0.3, and P(Aᶜ ∩ B) = 0.3. C. P(A ∩ B) = 0.1, P(A ∩ B) = 0.1, and P(Aᶜ ∩ B) = 0.4. D. P(A ∩ Bᶜ) = 0.3, P(A ∩ B) = 0.0, and P(Aᶜ ∩ B) = 0.2. E. P(A ∩ Bᶜ) = 0.5, P(A ∩ B) = 0.1, and P(Aᶜ ∩ B) = 0.4. Pago 12
12. Ms. Tucker travels through two intersections with traffic lights as she drives to the market. The traffic lights operate independently. The probability that both lights will be red when she reaches them is 0.22. The probability that the first light will be red and the second light will not be red is 0.33. What is the probability that the second light will be red when she reaches it? A. 0.40 B. 0.45 C. 0.50 D. 0.55 E. 0.60 Pago 12
13. In a certain school, 17 percent of the students are enrolled in a psychology course, 28 percent are enrolled in a foreign language course, and 32 percent are enrolled in either a psychology course or a foreign language course or both. What is the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course? A. 0.45 B. 0.32 C. 0.20 D. 0.13 E. 0.05 Pogo 14
14. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged during delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years? A. 0.05 B. 0.06 C. 0.10 D. 0.40 E. 0.50 Pogo 15
15. A student is applying to two different agencies for scholarships. Based on the stu- dent's academic record, the probability that the student will be awarded a schol- arship from Agency A is 0.55 and the probability that the student will be awarded a scholarship from Agency B is 0.40. Furthermore, if the student is awarded a scholarship from Agency A, the probability that the student will be awarded a scholarship from Agency B is 0.60. What is the probability that the student will be awarded at least one of the two scholarships? A. 0.60 B. 0.62 C. 0.71 D. 0.73 E. 0.95 2 Discrete Random Variables Page 16
1. The following table shows the probability distribution for the number of books a student typically buys at the annual book fair held at an elementary school. Number of Books 0 1 2 3 4 5 6 7 Probability 0.35 0.20 0.15 0.10 0.07 0.08 0.04 0.01 Let the random variable B represent the number of books a student buys at the next book fair. What is the expected value of B? A. 0 B. 1.00 C. 1.79 D. 3.50 E. 28 Page 17
2. At a large regional collegiate women's swim meet, an official records the time it takes each swimmer to swim 100 meters for all swimmers who compete in only one stroke category. The following table shows the mean times and corresponding standard deviations for the collegiate women at the swim meet for each of the four stroke categories. Stroke Category | Mean 100 meter Time Standard Deviation Backstroke 55.6 seconds 0.70 seconds Breaststroke 63.3 seconds 0.92 seconds Butterfly 54.4 seconds 0.94 seconds Freestyle 50.2 seconds 0.76 seconds For each of the 4 stroke categories, consider a random variable representing the time of a randomly selected swimmer in that category. What is the standard deviation of the sum of the 4 random variables? A. 0.83 seconds B. 1.67 seconds C. 2.80 seconds D. 3.32 seconds E. 3.76 seconds Page 18
3. A player pays $15 to play a game in which a chip is randomly selected from a bag of chips. The bag contains 10 red chips, 4 blue chips, and 6 yellow chips. The player wins $5 if a red chip is selected, $10 if a blue chip is selected, and $20 if a yellow chip is selected. Let the random variable X represent the amount won from the selection of the chip, and let the random variable W represent the total amount won, where W = X – 15. What is the mean of W? A. $10.50 B. $4.50 C. -$4.50 D. -$6.50 E. -$10.50 Page 10
4. A city department of transportation studied traffic congestion on a certain highway. To encourage carpooling, the department will recommend a carpool lane if the average number of people in passenger cars on the highway is less than 2. The probability distribution of the number of people in passenger cars on the highway is shown in the table. Number of people 1 2 3 4 5 Probability 0.56 0.28 0.08 0.06 0.02 - Based on the probability distribution, what is the the mean number of people in pas- senger cars on the highway? ☆たんX.std(y)=nStd(x) nt Xi A. 0.28 B. 0.56 C. 1.7 D. 2 E. 3 当xit………+Xn.xiid with Mx, 6x. Gy=In Ox.. Pogo 20
5. Every Thursday, Matt and Dave's Video Venture has "roll-the-dice" day. A cus- tomer may choose to roll two fair dice and rent a second movie for an amount (in cents) equal to the numbers uppermost on the dice, with the larger number first. Let X represent the amount paid for a second movie on roll-the-dice day. The expected value of X is $0.47 and the standard deviation of X is $0.15. If a customer rolls the dice and rents a second movie every Thursday for 30 consecutive weeks, what is the approximate probability that the total amount paid for these second movies will exceed $15.00? A. 0 B. 0.09 C. 0.147 D. 0.86 0.868 E. 0.91 X~? E(X)=a47 Std(x)=0.15 Y=Xi YNN because Cib.T. 30 30 E(Y)=E(xi)=E(Xi)=30×0.47 P(Y>15) = 01366 130×0.152 30 Norrs2f.... 40, 153 Pogo 21
6. The distribution of random variable R has mean 10 and standard deviation 4. The distribution of random variable S has mean 7 and standard deviation 3. If R and S are independent, what are the mean and standard deviation of the distribution of R - S? A. Mean 3 and standard deviation 1 B. Mean 3 and standard deviation 5 C. Mean 3 and standard deviation 7 D. Mean 17 and standard deviation 1 E. Mean 17 and standard deviation 5 Page 22
7. At a certain bakery, the price of each doughnut is $1.50. Let the random variable D represent the number of doughnuts a typical customer purchases each day. The expected value and variance of the probability distribution of D are 2.6 dough- nuts and 3.6 (doughnuts)², respectively. Let the random variable P represent the price of the doughnuts that a typical customer purchases each day. Which of the following is the standard deviation, in dollars, of the probability distribution of P? A. 1.5(3.6) B. 1.5√3.6 C. √1.5(3.6) D. 1.5(2.6) E. 1.5√2.6 Page 2२
8. The XYZ Office Supplies Company sells calculators in bulk at wholesale prices, as well as individually at retail prices. The following tables are estimates for next year's sales. WHOLESALE SALES Number Sold 2,000 5,000 10,000 20,000 Probability 0.1 0.3 0.4 0.2 RETAIL SALES Number Sold 600 1,000 1,500 Probability 0.4 0.5 0.1 What profit does XYZ Office Supplies Company expect to make for the next year if the profit from each calculator sold is $20 at wholesale and $30 at retail? A. $10,590 B. $220,700 C. $264,750 D. $833,100 E. $1,002,500 Pogo 24
9. In a certain game, a fair die is rolled and a player gains 20 points if the die shows a "6." If the die does not show a "6," the player loses 3 points. If the die were to be rolled 100 times, what would be the expected total gain or loss for the player? A. A gain of about 1,700 points B. A gain of about 583 points C. A gain of about 83 points D. A loss of about 250 points E. A loss of about 300 points Page 25
10. A box contains 10 tags, numbered 1 through 10, with a different number on each tag. A second box contains 8 tags, numbered 20 through 27, with a different number on each tag. One tag is drawn at random from each box. What is the expected value of the sum of the numbers on the two selected tags? A. 13.5 B. 14.5 C. 15.0 D. 27.0 E. 29.0 Pogo 26
11. Let X represent the number on the face that lands up when a fair six-sided number cube is tossed. The expected value of X is 3.5, and the standard deviation of X is approximately 1.708. Two fair six-sided number cubes will be tossed, and the numbers appearing on the faces that land up will be added. Which of the following values is closest to the standard deviation of the resulting sum? A. 1.708 B. 1.848 C. 2.415 D. 3.416 E. 5.835 Page 27
12. A company that makes fleece clothing uses fleece produced from two farms, North- ern Farm and Western Farm. Let the random variable X represent the weight of fleece produced by a sheep from Northern Farm. The distribution of X has mean 14.1 pounds and standard deviation 1.3 pounds. Let the random variable Y repre- sent the weight of fleece produced by a sheep from Western Farm. The distribution of Y has mean 6.7 pounds and standard deviation 0.5 pound. Assume X and Y are independent. Let W equal the total weight of fleece from 10 randomly selected sheep from Northern Farm and 15 randomly selected sheep from Western Farm. Which of the following is the standard deviation, in pounds, of W? A. 1.3 + 0.5 B. √1.3² + 0.5² C. √10(1.3)² + 15(0.5)² D. √10²(1.3)² + 15²(0.5)² E. (1.3² + 0.5²)/10 + 15 3 The Normal Distribution Page 28
1. Two college roommates have each committed to donating to charity each week for the next year. The roommates' weekly incomes are independent of each other. Suppose the amount donated in a week by one roommate is approximately normal with mean $30 and standard deviation $10, and the amount donated in a week by the other roommate is approximately normal with mean $60 and standard deviation $20. Which of the following is closest to the expected number of weeks in a 52-week year that their combined donation will exceed $120? A. 0; the combined donation never exceeds $120 in a week B. 1 week C. 3 weeks D. 5 weeks E. 8 weeks Pogo 20
2. The distribution of random variable R has mean 10 and standard deviation 4. The distribution of random variable S has mean 7 and standard deviation 3. If R and S are independent, what are the mean and standard deviation of the distribution of R - S? A. Mean 3 and standard deviation 1 B. Mean 3 and standard deviation 5 C. Mean 3 and standard deviation 7 D. Mean 17 and standard deviation 1 E. Mean 17 and standard deviation 5 Page 30
3. A summer resort rents rowboats to customers but does not allow more than four people to a boat. Each boat is designed to hold no more than 800 pounds. Suppose the distribution of adult males who rent boats, including their clothes and gear, is normal with a mean of 190 pounds and standard deviation of 10 pounds. If the weights of individual passengers are independent, what is the probability that a group of four adult male passengers will exceed the acceptable weight limit of 800 pounds? A. 0.023 B. 0.046 C. 0.159 D. 0.317 E. 0.977 Page 21
4. Carly commutes to work, and her commute time is dependent on the weather. When the weather is good, the distribution of her commute times is approxi- mately normal with mean 20 minutes and standard deviation 2 minutes. When the weather is not good, the distribution of her commute times is approximately normal with mean 30 minutes and standard deviation 4 minutes. Suppose the probability that the weather will be good tomorrow is 0.9. Which of the following is closest to the probability that Carly's commute time tomorrow will be greater than 25 minutes? A. 0.0056 B. 0.0894 C. 0.0950 D. 0.8055 E. 0.9006 Page 32
5. Sean and Evan are college roommates who have part-time jobs as servers in restau- rants. The distribution of Sean's weekly income is approximately normal with mean $225 and standard deviation $25. The distribution of Evan's weekly income is approximately normal with mean $240 and standard deviation $15. Assuming their weekly incomes are independent of each other, which of the following is closest to the probability that Sean will have a greater income than Evan in a randomly selected week? A. 0.067 B. 0.159 C. 0.227 D. 0.303 E. 0.354 Page 2२
6. A company ships gift baskets that contain apples and pears. The distributions of weight for the apples, the pears, and the baskets are each approximately normal. The mean and standard deviation for each distribution is shown in the table below. The weights of the items are assumed to be independent. Item Mean Standard Deviation Apple 4.72 ounces 0.20 ounce Pear 5.41 ounces 0.18 ounce Basket 13.25 ounces 1.88 ounces Let the random variable W represent the total weight of 4 apples, 6 pears, and 1 basket. Which of the following is closest to the standard deviation of W? A. 1.90 ounces B. 1.97 ounces C. 2.26 ounces D. 3.76 ounces E. 3.83 ounces Pogo 34
7. The Attila Barbell Company makes bars for weight lifting. The weights of the bars are independent and are normally distributed with a mean of 720 ounces (45 pounds) and a standard deviation of 4 ounces. The bars are shipped 10 in a box to the retailers. The weights of the empty boxes are normally distributed with a mean of 320 ounces and a standard deviation of 8 ounces. The weights of the boxes filled with 10 bars are expected to be normally distributed with a mean of 7,520 ounces and a standard deviation of A. √12 ounces B. √80 ounces C. √224 ounces D. 48 ounces E. √1,664 ounces Page 35
8. The continuous random variable N has a normal distribution with mean 7.5 and standard deviation 2.5. For which of the following is the probability equal to 0? A. P(N = 8) B. P(N > 8) C. P(N &lt; 8) D. P(7 &lt; N &lt; 8) E. P(N &lt; 7) or P(N > 8) 4 Binomial and Geometric Distributions Pogo 36
1. A large store has a customer service department where customers can go to ask for help with store-related issues. According to store records, approximately 1/4 of all customers who go to the service department ask for help finding an item. Assume the reason each customer goes to the service department is independent from customer to customer. Based on the approximation, what is the probability that at least 1 of the next 4 customers who go to the service department will ask for help finding an item? A. 4 (1/4) B. 1 - (1/4) C. 1-(3/4) D. 4 (1/4)¹ (3/4)³ E. (1/4)(3/4)(2/4)(1/4) Page 27
2. Based on his past record, Luke, an archer for a college archery team, has a prob- ability of 0.90 of hitting the inner ring of the target with a shot of the arrow. Assume that in one practice Luke will attempt 5 shots of the arrow and that each shot is independent from the others. Let the random variable X represent the number of times he hits the inner ring of the target in 5 attempts. What is the probability that the number of times Luke will hit the inner ring of the target out of the 5 attempts is less than the mean of X? A. 0.40951 B. 0.50000 C. 0.59049 D. 0.91854 E. 0.99144 Page 28
3. Mateo plays on his school basketball team. From past history, he knows that his probability of making a basket on a free throw is 0.8. Suppose he wants to create a simulation using random numbers to estimate the probability of making at least 3 baskets on his next 5 free throw attempts. Which of the following assignments of the digits 0 to 9 could be used for the simulation? A. Let the even digits represent making a basket and the odd digits represent not making a basket. B. Let the digits 0 and 1 represent making a basket and the digits from 2 to 9 represent not making a basket. C. Let the digits from 0 to 3 represent making a basket and the digits from 4 to 9 represent not making a basket. D. Let the digits from 0 to 6 represent making a basket and the digits from 7 to 9 represent not making a basket. E. Let the digits from 0 to 7 represent making a basket and the digits 8 and 9 represent not making a basket. Pogo 20
4. According to a recent survey, 31 percent of the residents of a certain state who are age 25 years or older have a bachelor's degree. A random sample of 50 residents of the state, age 25 years or older, will be selected. Let the random variable B represent the number in the sample who have a bachelor's degree. What is the probability that B will equal 40? A. (50 choose 40) (0.31)⁴⁰ (0.69)¹⁰ B. (50 choose 40) (0.69)⁴⁰(0.31)¹⁰ C. (50 choose 10) (0.31)⁴⁰(0.69)¹⁰ D. (50 choose 10) (0.69)⁴⁰(0.31)¹⁰ E. 40(0.31)⁵⁰ Page 40
5. A blind taste test will be conducted with 9 volunteers to determine whether people can taste a difference between bottled water and tap water. Each participant will taste the water from two different glasses and then identify which glass he or she thinks contains the tap water. Assuming that people cannot taste a difference between bottled water and tap water, what is the probability that at least 8 of the 9 participants will correctly identify the tap water? A. 0.0020 B. 0.0195 C. 0.8889 D. 0.9805 E. 0.9980 Pogo 41
6. In a certain board game, a player rolls two fair six-sided dice until the player rolls doubles (where the value on each die is the same). The probability of rolling doubles with one roll of two fair six-sided dice is 1/6. What is the probability that it takes three rolls until the player rolls doubles? A. (1/6)³ B. (5/6)³ C. (1/6)(5/6)³ D. (1/6)(5/6)² E. (5/6)(1/6)² Page 12
7. A company that ships crystal bowls claims that bowls arrive undamaged in 95 percent of the shipments. Let the random variable G represent the number of shipments with undamaged bowls in 25 randomly selected shipments. Random variable G follows a binomial distribution with a mean of 23.75 shipments and a standard deviation of approximately 1.09 shipments. Which of the following is the best interpretation of the mean? A. Every shipment of 25 bowls will have 23.75 undamaged bowls. B. Every shipment of 25 bowls will have 23.75 damaged bowls. C. On average, the company receives 23.75 shipments before receiving the first shipment with a damaged bowl. D. For all possible shipments of size 25, the average number of damaged shipments is equal to 23.75. E. For all possible shipments of size 25, the average number of undamaged shipments is equal to 23.75. Pago 12
8. The transaction history at an electronic goods store indicates that 21 percent of customers purchase the extended warranty when they buy an eligible item. Sup- pose customers who buy eligible items are chosen at random, one at a time, until one is found who purchased the extended warranty. Let the random variable X represent the number of customers it takes to find one who purchased the extended warranty. Assume customers' decisions on whether to purchase the extended war- ranty are independent. Which of the following is closest to the probability that X > 3? A. 0.131 B. 0.390 C. 0.493 D. 0.507 E. 0.624 Pogo 44
9. According to a recent survey, 81 percent of adults in a certain state have graduated from high school. If 15 adults from the state are selected at random, what is the probability that 5 of them have not graduated from high school? A. (20 choose 28) (0.19)¹⁵(0.81)⁵ B. (15 choose 5) (0.19)¹⁵(0.81)¹⁵ C. (15 choose 5) (0.81)⁵(0.19)¹⁰ D. (15 choose 5) (0.19)⁵(0.81)¹⁰ E. (15 choose 5) (0.81)⁵(0.19)¹⁰ Page 45
10. A recent study reported that 45 percent of adults in the United States now get all their news online. A random sample of 8 adults in the United States will be selected. What is the probability that 6 of the selected adults get all their news online? A. (8 choose 6) (0.45)⁸(0.55)² B. (8 choose 6) (0.45)⁶(0.55)² C. (8 choose 2) (0.45)²(0.55)⁸ D. (8 choose 6) (0.45)⁶(0.55)² E. (8 choose 8) (0.45)⁸(0.55)⁶ 5 Sampling Distributions Pogo 146
1. For which of the following conditions is it not appropriate to assume that the sampling distribution of the sample mean is approximately normal? A. A random sample of 8 taken from a normally distributed population B. A random sample of 50 taken from a normally distributed population C. A random sample of 10 taken from a population distribution that is skewed to the right D. A random sample of 75 taken from a population distribution that is skewed to the left E. A random sample of 100 taken from a population that is uniform Pogo 17
2. Researchers working for a certain airline are investigating the weight of carry-on bags. The researchers will use the mean weight of a random sample of 800 carry-on bags to estimate the mean weight of all carry-on bags for the airline. Which of the following best describes the effect on the bias and the variance of the estimator if the researchers increase the sample size to 1,300? A. The bias will decrease and the variance will remain the same. B. The bias will increase and the variance will remain the same. C. The bias will remain the same and the variance will decrease. D. The bias will remain the same and the variance will increase. E. The bias will decrease and the variance will decrease. Page 148
3. A bag contains chips of which 27.5 percent are blue. A random sample of 5 chips will be selected one at a time and with replacement. What are the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5? A. The mean is 5(0.275), and the standard deviation is √5(0.275)(0.725). B. The mean is 0.275, and the standard deviation is √0.275(0.725). C. The mean is 0.275, and the standard deviation is √(0.275)(0.725)/5 D. The mean is 27.5, and the standard deviation is √5(27.5)(72.5). E. The mean is 27.5, and the standard deviation is √(27.5)(72.5)/5 Page 40
4. In two common species of flowers, A and B, the proportions of flowers that are blue are pa and pb, respectively. Suppose that independent random samples of 50 species-A flowers and 100 species-B flowers are selected. Let pa be the sample pro- portion of blue species-A flowers and pb be the sample proportion of blue species-B flowers. What is the mean of the sampling distribution of pa - pb? A. pa - pb B. (pa/50) - (pb/100) C. pa - pb D. √(pa(1-pa)/50 + pb(1-pb)/100) E. √(pa(1-pa)/50 + pb(1-pb)/100) Page 50
5. Suppose the variance in trunk diameter of the giant sequoia tree species is 15.7 m², while the variance in trunk diameter of the California redwood tree species is 10.6 m². Let x1 represent the average trunk diameter of four randomly sampled giant sequoia trees, and let x2 represent the average trunk diameter of three ran- domly sampled California redwood trees. If the random sampling is done with replacement, what is the standard deviation σ(x1-x2) of the sampling distribution of the difference in sample means x1 - x2? A. √(15.7/4 - 10.6/3) B. 15.7 – 10.6 C. √(15.7/4 + 10.6/3) D. √(15.7 + 10.6)/4 + 3 E. (15.7 + 10.6)/(4 + 3) Pogo 51
6. A manufacturer of cell phone batteries claims that the average number of recharge cycles for its batteries is 400. A consumer group will obtain a random sample of 100 of the manufacturer's batteries and will calculate the mean number of recharge cycles. Which of the following statements is justified by the central limit theorem? A. The distribution of the number of recharge cycles for the sample is ap- proximately normal because the population mean of 400 is greater than 30. B. The distribution of the number of recharge cycles for the sample is ap- proximately normal because the sample size of 100 is greater than 30. C. The distribution of the number of recharge cycles for the population is approximately normal because the sample size of 100 is greater than 30. D. The distribution of the sample means of the number of recharge cycles is approximately normal because the sample size of 100 is greater than 30. E. The distribution of the sample means of the number of recharge cycles is approximately normal because the population mean of 400 is greater than 30. Page 52
7. The normal curve shown represents the sampling distribution of a sample mean for sample size n = 25, selected at random from a population with standard deviation σx. (Refer to the image in the original prompt where a normal curve is shown with an x-axis span.) Which of the following is the best estimate of the standard deviation of the population, σx? A. 3 B. 6 C. 15 D. 30 E. 75 Page 52
8. Based on records kept at a gas station, the distribution of gallons of gas purchased by customers is skewed to the right with mean 10 gallons and standard deviation 4 gallons. A random sample of 64 customer receipts was selected, and the sample mean number of gallons was recorded. Suppose the process of selecting a random sample of 64 receipts and recording the sample mean number of gallons was re- peated for a total of 100 samples. Which of the following is the best description of a dotplot created from the 100 sample means? A. The dotplot is skewed to the right with mean 10 gallons and standard deviation 4 gallons. B. The dotplot is skewed to the right with mean 10 gallons and standard deviation 0.5 gallon. C. The dotplot is skewed to the right with mean 10 gallons and standard deviation 0.4 gallon. D. The dotplot is approximately normal with mean 10 gallons and standard deviation 0.5 gallon. E. The dotplot is approximately normal with mean 10 gallons and standard deviation 0.4 gallon. Poco 54
9. The director of a marketing department wants to estimate the proportion of people who purchase a certain product online. The director originally planned to obtain a random sample of 2,500 people who purchased the product. However, because of budget concerns, the sample size will be reduced to 1,500 people. Which of the following describes the effect of reducing the number of people in the sample? A. The variance of the sample will increase. B. The variance of the population will decrease. C. The variance of the sampling distribution of the estimator will increase. D. The variance of the sampling distribution of the estimator will decrease. E. The variance of the sampling distribution of the estimator will remain the same. gy wood
10. The graph shows the population distribution of random variable X with mean 85 and standard deviation 18. (The graph shows a skewed distribution). Which of the following graphs is a sampling distribution of the sample mean for samples of size 40 taken from the population? A. A graph similar to the population (skewed). B. A graph slightly less skewed. C. An approximately normal distribution centered at 85 with smaller spread. D. An approximately normal distribution centered at 85 with larger spread. E. A uniform distribution. (Note: Based on CLT, for n = 40, the sampling distribution should be approxi- mately normal). Page 56
11. Two different drugs, X and Y, are currently in use to treat a certain condition. About 7 percent of the people using either drug experience side effects. A random sample of 75 people using drug X and a random sample of 150 people using drug Y are selected. The proportion of people in each sample who experience side effects is recorded. Are the sample sizes large enough to assume that the sampling distribution of the difference in sample proportions is approximately normal? A. Yes. Both sample sizes are large enough. B. No. The sample size for drug X is large enough, but the sample size for drug Y is not. C. No. The sample size for drug Y is large enough, but the sample size for drug X is not. D. No. Neither sample size is large enough. E. There is not enough information provided to determine whether the sam- pling distribution is approximately normal. Page 57
12. A recent survey concluded that the proportion of American teenagers who have a cell phone is 0.27. The true population proportion of American teenagers who have a cell phone is 0.29. For samples of size 1,000 that are selected at random from this population, what are the mean and standard deviation, respectively, for the sampling distribution of the sample proportion of American teenagers who have a cell phone? A. 0.27, √(1000)(0.27)(0.73) B. 0.27, √((0.29)(0.71))/1000 C. 0.27, √((0.27)(0.73))/1000 D. 0.29, √((0.29)(0.71))/1000 E. 0.29, √(1000)(0.29)(0.71) Page 58
13. A reading specialist wanted to estimate the mean word length, in number of letters, for an elementary school history textbook. The specialist took repeated random samples of size 100 words and estimated the mean and standard deviation of the sampling distribution to be 4.9 letters and 0.15 letter, respectively. Based on the estimates for the sampling distribution, which of the following provides the best estimates of the population parameters? A. Mean 4.9 letters and standard deviation 0.015 letter B. Mean 4.9 letters and standard deviation 0.15 letter C. Mean 4.9 letters and standard deviation 1.5 letters D. Mean 0.49 letter and standard deviation 0.15 letter E. Mean 49 letters and standard deviation 15 letters Page 50
&lt;/div></description></item><item><title>Note Update: Foundations of Probability and Discrete Random Variables</title><link>https://ap-stat.zhtek.org/notes/ap2/</link><pubDate>Wed, 24 Dec 2025 04:45:03 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/ap2/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/ap2.webp" alt="Featured image of post Note Update: Foundations of Probability and Discrete Random Variables" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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Multiplication Rule. Tree Diagram P(A∩B)=P(A) • P(B) ← independent cond. = P(A) • P(B|A) ← not independent ↑ Vienn Diagrim. Addition Rule Conditional prob. P(A∪B) = P(A)+P(B) ← mutually exclusive. A B = P(A)+P(B)-P(A∩B) Classic. Probability Model. P(A)= # of outcomes in A. # of outcomes in S Only when all outcomes are equally likely to happen Geometric Prob.. Model. P(A)= Area(A) / Area(S)=1. ← Calc. = Area(A) → Formula.Calculation of conditional prob. P(B|A) = P(A∩B) / P(A). ↳ Bayes Formula. Definition of independent. P(B|A)=P(B). P(A∩B)=P(A) • P(B). Mutually. Exclusive. 互斥. A∩B=Φ. P(A∩B)=0. no overlap 独立一定不互斥。 互斥一定不独立Probability Rule 1) Range of Prob. 0 ≤ P ≤ 1 2). Prob. of all outcomes is 1. 3). Complement Rule. P(A^c) = 1-P(A)Prob for a single event. 1) equally likely outcomes Classic Prob. Model. P(A) = # of outcomes in A / # of outcomes in S or # of total outcomes Think about fair coin toss, roll dice.... 2) Outcomes are not equally likely or infinite number of outcomes. 0.05R 0.25P 0.7G Geometric Prob. model.. P(A) = Area(A) / Area(S) = Area(A). Prob. for 2 event Weighted coin 0.7 H 0.7 H HH 0.49 0.3 T HT 0.21 H TH 0.21 0.3 T TT 0.09HH 0.49 B={TH, TT} HT 0.21 TH 0.21 TT 0.09 = 0.21+0.09 A^c A∩B A∪B A|B. multiplication rule P(A∩B) = P(A) • P(B|A) = P(B) • P(A|B). General addition rule P(A∪B) = P(A)+P(B)-P(A∩B): General P(A|B) = P(A∩B) / P(B). Bayes formula ↑ 条件是分母,相交是分子 Independent when Independent P(A|B)= P(A). &lt;=> P(A∩B) = P(A) • P(B) Mutually exclusive. when M.E P(A∩B)=0 &lt;=> P(A∪B) = P(A)+P(B)Random Event ⇒ Random Variable. Random Variable { Categorical Quantitative: ↓ ↓ {X=1.5, 1.5≤X≤1.8} {X=Red} ↑ ↑ ↑ Event A B C P(C) → cal like before with Prob. model P(A) &amp; P(B) {X→ generic distribution (X→ special distribution X→ generic distribution P(1.5≤X&lt;1.6) 1.5-1.6 108 209 = 108 / 337 1.6-1.7 121. 1.8-1.9 88 1.9- 20 128 337P(X=1.5). X→ Special Distributions → discrete → binomial → geometric continuous → normal → uniform. Random Variable X. parameters E(X). Expected Value. aka. Mean. 期望值 均值 defn: E(X)=Σxi•pi ↓ Mx X 0 1 2 3 Pi 0.3 0.2 0.1 0.4 Mx = E(X) = 0x0.3 + 1x0.2+2x0.1 +3x0.4 = 1.6It's the center of distribution of X. How to interprete. 1.6. expected value for X. Statement: The expected height for random selected girls of HW is 1.62m How to interpret the 1.62m expected Value. After repeated trials of randomly selecting girls and take their height the long run average of girls height is. 1.62m. Standard Deviations / Variances of Random variable σ_x^2 = Var(X) = Σ (xi - E(X))^2 Pi = Σ(xi - E(X))^2 / n (last part crossed out,
&lt;/div></description></item><item><title>Note Update: Probability, Discrete Variables, Normal, Binomial, Geometric, and Sampling Distributions</title><link>https://ap-stat.zhtek.org/notes/prob-3/</link><pubDate>Wed, 24 Dec 2025 04:44:41 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/prob-3/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/prob-3.webp" alt="Featured image of post Note Update: Probability, Discrete Variables, Normal, Binomial, Geometric, and Sampling Distributions" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unknown | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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1 Probability: General Rules, Independence, and Conditional Probability 1. A high school science teacher has 78 students. Of those students, 35 are in the band and 32 are on a sports team. There are 16 students who are not in the band or on a sports team. One student from the 78 students will be selected at random. Let event B represent the event of selecting a student in the band, and let event S represent the event of selecting a student on a sports team. Are B and S mutually exclusive events?A. No, because P(BnS) = .578.B. No, because P(B ∩S)=4878.C. No, because P(B ∩S) =6278D. Yes, because P(BnS) =578E. Yes, because P(BnS) =6278.Page 2 Team Home Away Total 2. Purchased food 120 40 160 Did not purchase food 60 30 90 Total 180 70 250 The table shows data that were collected from people who attended a certain high school basketball game. A person who attended the game will be selected at ran-dom. Which of the following correctly interprets mutually exclusive events repre-sented by the table?A. Rooting for the home team and rooting for the away teamB. Rooting for the home team and purchasing food during the gameC. Rooting for the away team and purchasing food during the gameD. Rooting for the home team and not purchasing food during the gameE. Not rooting for the home team and not purchasing food during the game Page 3 3. A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at random to participate in the county chess tournament. What is the probability that Adam and Ella will be selected?A.120B.110C.1-81-71-4Ε.Page 4 4. Events D and E are independent, with P(D) = 0.6 and P(D and E) = 0.18.Which of the following is true?A. P(E) = 0.12B. P(E) = 0.4C. P(D or E) = 0.28D. P(D or E) = 0.72E. P(D or E) = 0.9Page 5 5. One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, and let B be the event that the selected student drives to school. If P(A ∩ B) = 0.08 and P(B | A) = 0.25, what is the probability that the selected student will be a student athlete?A. 0.02B. 0.17C. 0.32D. 0.33Ε. 3.13Page 6 6. Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appearing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6?A. 2/36Β. 3/36C. 3/15D. 2/9Ε. 4/6Page 7 7. As a promotion, the first 50 customers who entered a certain store at a mall were asked to choose from one of two discounts. The first discount choice was 20% off all purchases made that day. The second discount choice was 10% off all purchases for the week. Of those who received the discounts, 28 chose the first discount and 22 chose the second discount. One customer will be selected at random from those who received a discount. Let F represent the event that the selected person chose the first discount, and let S represent the event that the selected person chose the second discount. Are F and S mutually exclusive events?A. Yes, because P(F∩S) = 0.B. Yes, because P(F∩S) = 0.12.C. Yes, because P(F∩S) = 1.D. No, because P(F∩S) = 0.E. No, because P(F ∩ S) = 1.Page 8 8. For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem. If one flight is selected at random from the airport in January, what is the probability that the flight selected will have at least one of the two types of delays?A. 0.065Β. 0.335C. 0.350D. 0.450Ε. 0.665Page 9 9. Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. Of the 80 male students who were surveyed, 60 had brown eyes. If eye color and gender are independent, how many female students surveyed would be expected to have brown eyes?A. 5B. 20C. 30D. 90Ε. 100Page 10 10. The SC Electric Company has bid on two electrical wiring jobs. The owner of the company believes that• the probability of being awarded the first job (event A) is 0.75;• the probability of being awarded the second job (event B) is 0.5; and• the probability of being awarded both jobs (event (A and B)) is 0.375.If the owner's beliefs are correct, which of the following statements must be true concerning event A and event B?A. Event A and event B are mutually exclusive and are independent.B. Event A and event B are mutually exclusive and are not independent.C. Event A and event B are not mutually exclusive and are independent.D. Event A and event B are not mutually exclusive and are not independent.E. Event A and event B are not mutually exclusive, and independence cannot be determined.Page 11 11. For which of the following probability assignments are events A and B indepen-dent?A. P(A ∩ B) = 0.3, P(A ∩ B) = 0.12, and P(A∩ B) = 0.4.B. P(A ∩ Bº) = 0.3, P(A ∩ B) = 0.3, and P(A∩ B) = 0.3.C. P(A ∩ B) = 0.1, P(A ∩ B) = 0.1, and P(A∩ B) = 0.4.D. P(A ∩ Bº) = 0.3, P(A ∩ B) = 0.0, and P(A∩ B) = 0.2.E. P(A ∩ Bº) = 0.5, P(A ∩ B) = 0.1, and P(A∩ B) = 0.4.Page 12 12. Ms. Tucker travels through two intersections with traffic lights as she drives to the market. The traffic lights operate independently. The probability that both lights will be red when she reaches them is 0.22. The probability that the first light will be red and the second light will not be red is 0.33. What is the probability that the second light will be red when she reaches it?A. 0.40Β. 0.45C. 0.50D. 0.55Ε. 0.60Page 13 13. In a certain school, 17 percent of the students are enrolled in a psychology course, 28 percent are enrolled in a foreign language course, and 32 percent are enrolled in either a psychology course or a foreign language course or both. What is the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course?A. 0.45B. 0.32C. 0.20D. 0.13Ε. 0.05Page 14 14. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged during delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years?A. 0.05B. 0.06C. 0.10D. 0.40Ε. 0.50Page 15 15. A student is applying to two different agencies for scholarships. Based on the stu-dent's academic record, the probability that the student will be awarded a schol-arship from Agency A is 0.55 and the probability that the student will be awarded a scholarship from Agency B is 0.40. Furthermore, if the student is awarded a scholarship from Agency A, the probability that the student will be awarded a scholarship from Agency B is 0.60. What is the probability that the student will be awarded at least one of the two scholarships?A. 0.60B. 0.62C. 0.71D. 0.73Ε. 0.952 Discrete Random Variables Page 16 1. The following table shows the probability distribution for the number of books a student typically buys at the annual book fair held at an elementary school.5623470.35 0.20 0.15 0.10 0.07 0.08 0.04 0.01Number of Books 01ProbabilityLet the random variable B represent the number of books a student buys at the next book fair. What is the expected value of B?A. 0B. 1.00C. 1.79D. 3.50Ε. 28Page 17 2. At a large regional collegiate women's swim meet, an official records the time it takes each swimmer to swim 100 meters for all swimmers who compete in only one stroke category. The following table shows the mean times and corresponding standard deviations for the collegiate women at the swim meet for each of the four stroke categories.Stroke CategoryMean 100 meter Time Standard DeviationBackstroke55.6 seconds0.70 secondsBreaststroke63.3 seconds0.92 secondsButterfly54.4 seconds0.94 secondsFreestyle50.2 seconds0.76 secondsFor each of the 4 stroke categories, consider a random variable representing the time of a randomly selected swimmer in that category. What is the standard deviation of the sum of the 4 random variables?A. 0.83 secondsB. 1.67 secondsC. 2.80 secondsD. 3.32 secondsE. 3.76 secondsPage 18 3. A player pays $15 to play a game in which a chip is randomly selected from a bag of chips. The bag contains 10 red chips, 4 blue chips, and 6 yellow chips. The player wins $5 if a red chip is selected, $10 if a blue chip is selected, and $20 if a yellow chip is selected. Let the random variable X represent the amount won from the selection of the chip, and let the random variable W represent the total amount won, where W = X – 15. What is the mean of W?A. $10.50Β. $4.50C. -$4.50D. -$6.50Ε. -$10.50Page 19 4. A city department of transportation studied traffic congestion on a certain highway. To encourage carpooling, the department will recommend a carpool lane if the average number of people in passenger cars on the highway is less than 2. The probability distribution of the number of people in passenger cars on the highway is shown in the table.Number of people 1 2345Probability0.56 0.28 0.08 0.06 0.02Based on the probability distribution, what is the mean number of people in passenger cars on the highway?A. 0.28B. 0.56C. 1.7D. 2E. 3Page 20 5. Every Thursday, Matt and Dave's Video Venture has
&lt;/div></description></item><item><title>Note Update: Probability, Random Variables, and Sampling Distributions</title><link>https://ap-stat.zhtek.org/notes/prob/</link><pubDate>Wed, 24 Dec 2025 04:43:35 +0000</pubDate><guid>https://ap-stat.zhtek.org/notes/prob/</guid><description>&lt;img src="https://assets.zhtek.org/thumbs/prob.webp" alt="Featured image of post Note Update: Probability, Random Variables, and Sampling Distributions" />&lt;p>&lt;strong>Class:&lt;/strong> AP2 | &lt;strong>Unit:&lt;/strong> Unit 4 | &lt;strong>Updated:&lt;/strong> 2025-12-24&lt;/p>
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1 Probability: General Rules, Independence, and Conditional Probability 1. A high school science teacher has 78 students. Of those students, 35 are in the band and 32 are on a sports team. There are 16 students who are not in the band or on a sports team. One student from the 78 students will be selected at random. Let event B represent the event of selecting a student in the band, and let event S represent the event of selecting a student on a sports team. Are B and S mutually exclusive events? Steam. Ar 32 A No, because P(BnS) = . 5 78. 16 B. No, because P(BnS) = 48 78. B S C. No, because P(B
S) = 62 78 D. Yes, because P(BnS) = 5 78 E. Yes, because P(BnS) = %. 62 78. PCAUB) = 78-16=62 - 78 78 PLAUB) = P(A)+PCB) - PANB). 62 To = 35 32 18+ 78 - X 78 Page 2 Team Home Away Total 2. Purchased food 120 40 160 Did not purchase food 60 30 90 Total 180 70 250 The table shows data that were collected from people who attended a certain high school basketball game. A person who attended the game will be selected at ran- dom. Which of the following correctly interprets mutually exclusive events repre- sented by the table? A. Rooting for the home team and rooting for the away team B. Rooting for the home team and purchasing food during the game C. Rooting for the away team and purchasing food during the game D. Rooting for the home team and not purchasing food during the game E. Not rooting for the home team and not purchasing food during the game Page 2 3. A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at random to participate in the county chess tournament. What is the probability that Adam and Ella will be selected? A. 1 20 B. 1 10 A B C DE C. D. B CDE ACDE ABDE ABCE ABLD Ε. Page 4 2 二 4. Events D and E are independent, with P(D) = 0.6 and P(D and E) = 0.18. Which of the following is true? A. P(E) = 0.12 B. P(E) = 0.4 C. P(D or E) = 0.28 D. P(D or E) = 0.72 E. P(D or E) = 0.9 Page 5 5. One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, and let B be the event that the selected student drives to school. If P(A
B) = 0.08 and P(B | A) = 0.25, what is the probability that the selected student will be a student athlete? A. 0.02 B. 0.17 C. 0.32 D. 0.33 Ε. 3.13 PLANB) = PLA). PCBIA) 0.08 0.25 ↑ ? 0.08 PLA) = 0-25:0.32 Page 6 6. Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appearing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6? A. 2/36 Β. 3/36 C. 3/15 D. 2/9 Ε. 4/6 X.Y RV. P(X+Y=4 / X+Y26) 11-5 x5 21-4 31-3 4 1-2 51 x4 x2 23 136 こ Pogo 7 P(x+y=4}{X+Y=6}) 3 P(X+Y=6) 36 →PCX+Y=4) PCX+Y50) 36 7. As a promotion, the first 50 customers who entered a certain store at a mall were asked to choose from one of two discounts. The first discount choice was 20% off all purchases made that day. The second discount choice was 10% off all purchases for the week. Of those who received the discounts, 28 chose the first discount and 22 chose the second discount. One customer will be selected at random from those who received a discount. Let F represent the event that the selected person chose the first discount, and let S represent the event that the selected person chose the second discount. Are F and S mutually exclusive events? A. Yes, because P(F∩S) = 0. B. Yes, because P(F∩S) = 0.12. C. Yes, because P(F∩S) = 1. D. No, because P(F∩S) = 0. E. No, because P(F ∩ S) = 1. Page 8 8. For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem. If one flight is selected at random from the airport in January, what is the probability that the flight selected will have at least one of the two types of delays? A. 0.065 Β. 0.335 C. 0.350 PLIUM) D. 0.450 PLI)=a3 Ε. 0.665 азт Di delay Mal изход MC PCM11)=0.1 0.79C005M Txos PLM 174)=0.05 Page 0 9. Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. Of the 80 male students who were surveyed, 60 had brown eyes. If eye color and gender are independent, how many female students surveyed would be expected to have brown eyes? A. 5 B. 20 C. 30 D. 90 Ε. 100 Page 10 10. The SC Electric Company has bid on two electrical wiring jobs. The owner of the company believes that • the probability of being awarded the first job (event A) is 0.75; • the probability of being awarded the second job (event B) is 0.5; and • the probability of being awarded both jobs (event (A and B)) is 0.375. If the owner's beliefs are correct, which of the following statements must be true concerning event A and event B? A. Event A and event B are mutually exclusive and are independent. B. Event A and event B are mutually exclusive and are not independent. C. Event A and event B are not mutually exclusive and are independent. D. Event A and event B are not mutually exclusive and are not independent. E. Event A and event B are not mutually exclusive, and independence cannot be determined. Poco 11 11. For which of the following probability assignments are events A and B indepen- dent? A. P(A
B) = 0.3. P(A
B) = 0.12, and P(A
B) = 0.4. B. P(A
B) = 0.3, P(A
B) = 0.3, and P(A
B) = 0.3. C. P(A
Bº) = 0.1, P(A
B) =(0.1. and P(A
B) = 0.4. D. P(A
Bº) = 0.3, P(A
B) = 0.0, and P(A
B) = 0.2. E. P(A
B) = 0.5, P(A
B) = 0.1, and P(A
B) = 0.4. PCA
B)=P(A).P(13). Pago 12 12. Ms. Tucker travels through two intersections with traffic lights as she drives to the market. The traffic lights operate independently. The probability that both lights will be red when she reaches them is 0.22. The probability that the first light will be red and the second light will not be red is 0.33. What is the probability that the second light will be red when she reaches it? A0.40 Β. 0.45 C. 0.50 D. 0.55 Ε. 0.60 PLS) =? =0.22. P(FAS)=222) P(FMS)=0.33 055 0.22=P(FAS)=PLF) XP(S). 0.22 PCS) = 0.5 = 0.4 • ** ? Pago 12 KA 13. In a certain school, 17 percent of the students are enrolled in a psychology course, 28 percent are enrolled in a foreign language course, and 32 percent are enrolled in either a psychology course or a foreign language course or both. What is the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course? A. 0.45 B. 0.32 C. 0.20 D. 0.13 Ε. 0.05 917 P(44) = 0,170 VP(AUB)=432. P(B)=0,28 J VPCA1B)=? 0.28 P(AMB)=P(A). PCB) A&amp;B independent - 0.32. P(A)+PCB) - PC/UB) = P(AMB). P(AUB)=P(A)+PCB) - PANB). Pogo 14 14. 14/ The The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged during delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years? A. 0.05 B. 0.06 C. 0.10 D. 0.40 P(A)= 0.05 PCAIB)=? 0.04 PCANB)=0.04. PCA1B7= PLANB) Ε. 0.50 P(B)=0.1. Pogo 15 PCB) 이 15. A student is applying to two different agencies for scholarships. Based on the stu- dent's academic record, the probability that the student will be awarded a schol- arship from Agency A is 0.55 and the probability that the student will be awarded a scholarship from Agency B is 0.40. Furthermore, if the student is awarded a scholarship from Agency A, the probability that the student will be awarded a scholarship from Agency B is 0.60. What is the probability that the student will be awarded at least one of the two scholarships? A. 0.60 B. 0.62 C. 0.71 D. 0.73 Ε. 0.95 2 Discrete Random Variables Page 16 1. The following table shows the probability distribution for the number of books a student typically buys at the annual book fair held at an elementary school. Number of Books 0 1 2 3 4 5 f 6 7 Probability 0.35 0.20 0.15 0.10 0.07 0.08 0.04 0.01 Let the random variable B represent the number of books a student buys at the next book fair. What is the expected value of B? A. 0 B. 1.00 C. 1.79 D. 3.50 Ε. 28 Page 17 2. At a large regional collegiate women's swim meet, an official records the time it takes each swimmer to swim 100 meters for all swimmers who compete in only one stroke category. The following table shows the mean times and corresponding standard deviations for the collegiate women at the swim meet for each of the four stroke categories. Stroke Category Mean 100 meter Time Standard Deviation Backstroke 55.6 seconds 0.70 seconds Breaststroke 63.3 seconds 0.92 seconds Butterfly 54.4 seconds 0.94 seconds Freestyle 50.2 seconds 0.76 seconds For each of the 4 stroke categories, consider a random variable representing the time of a randomly selected swimmer in that category. What is the standard deviation of the sum of the 4 random variables? A. 0.83 seconds B. 1.67 seconds C. 2.80 seconds D. 3.32 seconds E. 3.76 seconds Page 18 3. A player pays $15 to play a game in which a chip is randomly selected from a bag of chips. The bag contains 10 red chips, 4 blue chips, and 6 yellow chips. The player wins $5 if a red chip is selected, $10 if a blue chip is selected, and $20 if a yellow chip is selected. Let the random variable X represent the amount won from the selection of the chip, and let the random variable W represent the total amount won, where W = X – 15. What is the mean of W? A. $10.50 Β. $4.50 C. -$4.50 D. -$6.50 Ε. -$10.50 Page 10 4. A city department of transportation studied traffic congestion on a certain highway. To encourage carpooling, the department will recommend a carpool lane if the average number of people in passenger cars on the highway is less than 2. The probability distribution of the number of people in passenger cars on the highway is shown in the table. Number of people 1 2 3 4 5 Probability 0.56 0.28 0.08 0.06 0.02 Based on the probability distribution, what is the mean number of people in passenger cars on the highway? A. 0.28 B. 0.56 C. 1.7 D. 2 E. 3 Page 20 5. Every Thursday, Matt and Dave's Video Venture has
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